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3 years ago

What is the slope of a line that is perpendicular to the line y=2x-6?

1 answer:

8 0

The answer is c because you have to use the slope form equation y=mx+b the m is the slope and the b is the y intercept. <span />

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Find the tenth term in the following geometric sequence. 8, 4, 2, 1, . . .

Marrrta [24]

Answer:

c) 0.0156

Step-by-step explanation:

The general term a[n] of a geometric sequence is given in terms of the first term a[1] and common ratio r as ...

a[n] = a[1]r^(n-1)

The given sequence has an initial term of a[1]=8 and a common ratio of 4/8=1/2. Then the general term is ...

a[n] = 8(1/2)^(n-1)

The 10th term is then ...

a[10] = 8(1/2)^(10-1) = 8(1/2)^9 = 8/512

a[10] = 0.015625 ≈ 0.0156

7 0

3 years ago

Please help ( if you can then please help with <br> both questions )

tatuchka [14]

Answer:

For number 1, -1.125 and -9/8. For number 2, -46.

Step-by-step explanation:

6 0

2 years ago

If Sean earns $8.50 per hour sand made a total of $80.75 today, How many hours did he work?

Serggg [28]

80.75 / 8.50 = 9.5
Sean worked 9 and a half hours.

8 0

3 years ago

Read 2 more answers

How to prove this???

swat32

$\cos^3 2A + 3 \cos 2A \\
\Rightarrow \cos 2A (\cos^2 2A + 3) \\
\Rightarrow (\cos^2 A - \sin^2 A) (\cos^2 2A + 3) \\
\Rightarrow (\cos^2 A - \sin^2 A) (1 - \sin^2 2A + 3) \\
\Rightarrow (\cos^2 A - \sin^2 A) (4 - \sin^2 2A) \\
\Rightarrow (\cos^2 A - \sin^2 A) (4 - (2\sin A \cos A)(2\sin A \cos A)) \\
\Rightarrow (\cos^2 A - \sin^2 A) (4 - 4\sin^2 A \cos^2 A) \\ 
\Rightarrow 4(\cos^2 A - \sin^2 A) (1 - \sin^2 A \cos^2 A) 
$

go to right side now

$4( \cos^6 A - \sin^6 A)\\
\Rightarrow 4( \cos^3 A - \sin^3 A)(\cos^3 A + \sin^3 A)$

use $x^3 - y^3 = (x-y)(x^2 + xy + y^2)$ and $x^3 + y^3 = x^2 - xy + y^2$

$4( \cos^6 A - \sin^6 A)\\ \Rightarrow 4( \cos^3 A - \sin^3 A)(\cos^3 A + \sin^3 A) \\
\Rightarrow 4(\cos A - \sin A)(\cos^2 A + \cos A \sin A + \sin^2 A) \\
~\quad \quad\cdot ( \cos A + \sin A)(\cos^2 A - \cos A \sin A + \cos^2 A)$

so $\sin^2 A + \cos^2 A = 1$

$4( \cos^6 A - \sin^6 A)\\ \Rightarrow 4(\cos A - \sin A)(\cos^2 A + \cos A \sin A + \sin^2 A) \\ ~\quad \quad\cdot ( \cos A + \sin A)(\cos^2 A - \cos A \sin A + \cos^2 A) \\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 + \cos A \sin A )(1- \cos A \sin A ) \\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 - \cos^2 A \sin^2 A )\\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 - \sin^2 A \cos^2 A ) \\
 \Rightarrow Left hand side$

4 0

3 years ago

Erin has 4 1/2 pounds of trail mix. She wants to make 3/4 pound bags of mix for snacks. How many bags can she make?

PtichkaEL [24]

Answer:

Step-by-step explanation:

4 1/2 = 9/2=18/4

(18/4)/(3/4)=18/3=6

so she need 6 bags

4 0

2 years ago