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3 years ago

What is the slope of the line that passes through the points (4, 10) and (1,10)?

Mathematics

2 answers:

Crazy boy [7]3 years ago

6 0

Answer:

Slope is 0

explanation:

Slope is the same as gradient.

Formular:

${ \boxed{ \bf{slope = \frac{y _{2} - y _{1}}{x _{2} - x _{1} } }}}$

Substitute the variables:

${ \tt{slope = \frac{10 - 10}{1 - 4} }} \\ \\ = { \tt{ \frac{0}{ - 3} }} \\ = 0$

Y_Kistochka [10]3 years ago

4 0

Answer:

Step-by-step explanation:

We have two points so we can use the sloe formula

m = (y2-y1)/(x2-x1)

= ( 10-10)/(1-4)

= 0/ -3

= 0

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What does 58x9234=????

Troyanec [42]

Answer:

535572

Step-by-step explanation:

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3 years ago

Verify the identity 6cos^2(x) -3 = 3 - 6sin^2(x)

Lorico [155]

Answer:

It is proved that $6\cos ^{2}x -3 = 3 - 6\sin ^{2} x$ .

Step-by-step explanation:

We already have the identity of x as $\sin ^{2}x + \cos ^{2}x = 1$ .......... (1) .

So, from equation (1) we can write that

$\cos ^{2} x = 1 - \sin ^{2} x$

⇒ $6\cos ^{2} x = 6 - 6 \sin ^{2} x$

⇒ $6\cos ^{2} x -3 = 6 - 6 \sin ^{2}x -3$

⇒ $6\cos ^{2}x -3 = 3 - 6\sin ^{2} x$

Hence, it is proved that $6\cos ^{2}x -3 = 3 - 6\sin ^{2} x$ . (Answer)

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3 years ago

amy places adopt on a coordinate plane at (-3,-6) she wants to place another dot across the y-axis and it must be 8 points away.

Vaselesa [24]

(5,-6) because across the y acis meanes the same y Val just a different x Val. and so you could count 8 away from -3 going right. and you'll get my answer

6 0

3 years ago

Read 2 more answers

HELP I WILL GIVE BRAINLEIST OR WHATEVER 50 POINTS

Ilya [14]

answer:

a. scarf costs today = $6

b. scarf costs 3 days from now = $3

step-by-step explanation:

1/2 off means you would multiply the amount by 1/2 then subtract

a. original price of scarf: $12

12 X 1/2 = 6

12 - 6 = 6

— scarf costs today = $6

do the same thing but this time it is a different number

b. 12 X 3/4 = 9

12 - 9 = 3

— scarf costs 3 days from now = $3

3 0

3 years ago

Find the area of the triangle formed by the origin and the points of intersection of parabolas y=− 1/3 (x−1)^2+8 and y=x^2−2x−3.

Kobotan [32]

Answer:

The area of the triangle formed by origin, and the points (4,5) and (-2,5) will be 15 sq. units.

Step-by-step explanation:

The two parabolas are $y = - \frac{1}{3}(x - 1)^{2} + 8$ and y = x² - 2x - 3.

Now, solving those two equations we will get the points of intersection.

So, $- \frac{1}{3}(x - 1)^{2} + 8 = x^{2} - 2x - 3$

⇒ - (x - 1)² + 24 = 3x² - 6x - 9

⇒ -x² + 2x - 1 + 24 = 3x² - 6x - 9

⇒ 4x² - 8x - 32 = 0

⇒ x² - 2x - 8 = 0

⇒ x² - 4x + 2x - 8 = 0

⇒ (x - 4)(x + 2) = 0

So, x = 4 or - 2.

Now, for x = 4 , y = 4² - 2(4) - 3 = 5 and the point of intersection is (4,5).

Or, for x = - 2, y = (- 2)² - 2(- 2) - 3 = 5 and the point of intersection is (-2,5).

Now, points (4,5) and (-2,5) make a straight line parallel to the x-axis at a perpendicular distance of 5 units from origin and its length is (4 - (- 2)) = 6 units.

So, the area of the triangle formed by origin, and the points (4,5) and (-2,5) will be = 0.5 × 5 × 6 = 15 sq. units. (Answer)

8 0

3 years ago