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3 years ago

What is the perimeter of a rectangle whose vertices are (2,7) (8,7) (211) (8,11)?

Mathematics

1 answer:

RoseWind [281]3 years ago

5 0

Answer:

e) 20

Step-by-step explanation:

Segment lengths:

|(2, 7) -> (8, 7)| = |(8-2, 7-7)| = |(6, 0)| = 6

|(8, 7) -? (8, 11)| = |(8-8, 11-7)| = |(0, 4)| = 4

because we know it's a rectangle, we can infer that the other two sides also have lengths 4 and 6, so the perimeter is 4+4+6+6=20

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1. X - 9 = 20

Verizon [17]

1. x=29

2. x=15

3. y=4

4. y=2

5. x=4

6. x=-21

7. y=63

8. x=12

9. x=-6

10. y=7

11. y=6

12. x=28

13. y=5

Hope it helps......

3 0

3 years ago

Sketch a graph of the following inequality and the choose the correct description of the graph: x + y - 5 ≥ 0

maxonik [38]

Answer:

Slope -1, y intercept +5.

Bold line, shaded above

Step-by-step explanation:

x + y - 5 ≥ 0

y ≥ -x + 5

3 0

3 years ago

Select 3 ratios that are equivalent to 4 : 3

Bad White [126]

Answer:

3 ratios that are equivelent to 4 : 3

8 : 6

20 : 15

and 12 : 9

Step-by-step explanation:

8 0

3 years ago

g An urn contains 10 balls: 4 red and 6 blue. A second urn contains 16 red balls and an unknown number of blue balls. A single b

Fed [463]

Answer:

Therefore the of blue in the second urn is 4.

Step-by-step explanation:

Let second urn contain x number of blue ball .

Urn Red Ball Blue Ball Total Ball

1 4 6 10

2 16 x 16+x

Getting a red ball from first urn is $P(R_1)=\frac{\textrm {Number of red ball}}{\textrm {Total ball}}$ $=\frac{4}{10}$

Getting a blue ball from first urn is $P(B_1)=\frac{\textrm {Number of blue ball}}{\textrm {Total ball}}$ $=\frac {6}{10}$

Getting a red ball from second urn is $P(R_2)=\frac{\textrm {Number of red ball}}{\textrm {Total ball}}$ $=\frac{16}{16+x}$

Getting a blue ball from second urn is $P(B_2)=\frac{\textrm {Number of blue ball}}{\textrm {Total ball}}$ $=\frac {x}{16+x}$

Getting two red balls from first and second urn is $=\frac{4}{10}\times \frac{16}{16+x}$

$=\frac{32}{5(16+x)}$

Getting two blue balls from first and second urn is $=\frac{6}{10}\times \frac{x}{16+x}$

$=\frac{3x}{5(16+x)}$

The probability that both balls are the same in color is $=\frac{32}{5(16+x)}+\frac{3x}{5(16+x)}$

Given that the probability that both balls are the same in color is 0.44.

According to the problem,

$\frac{32}{5(16+x)}+\frac{3x}{5(16+x)}=0.44$

$\Rightarrow \frac{32+3x}{5(16+x)} =0.44$

$\Rightarrow \frac {32+3x}{(80+5x)} =0.44$

$\Rightarrow 32+3x =0.44(80+5x)$

$\Rightarrow 32+3x =35.2 +2.2x$

$\Rightarrow 3x -2.2 x= 35.2 -32$

$\Rightarrow 0.8x= 3.2$

$\Rightarrow x = 4$

Therefore the of blue in the second urn is 4.

5 0

3 years ago

Mr. Fat needs 20 minutes to eat a pound of cereal, while Mr. Thin needs 30 minutes. If they eat together, how long does it take

marishachu [46]

36 minutes.

(1/20)x+(1/30)x=1solve for x (x=0.8333333333......)
Considering they take the same times for all 3 pounds,
That would mean that since 1 pound takes 12 minutes, then 3 pounds take 36 minutes

4 0

3 years ago