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Vesnalui [34]
3 years ago
9

Complete the function table and write the function rule.

Mathematics
1 answer:
arsen [322]3 years ago
6 0
To finish the table lets see what the differences are between the input (x) and the output (Y)

when input is 32 the output is 20, 32-20 = 12
when input is 14 the output is 2, 14-2 = 12

since the top 2 have the same result, the output is the input minus 12 
 now that we know that we can finish the table:

when the input is ? the output is -6, so the input = -6 +12 = 6
check: 6-12 = -6 true

when the input is -10, we subtract 12 to get -22 for the output
 so the missing input is 6 and the missing output is -22

 the function rule would be Y=x-12



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Answer:

Tara can make 60 bracelets.

Step-by-step explanation:

908 / 15 = 60.5

5 0
2 years ago
A door delivery florist wishes to estimate the proportion of people in his city that will purchase his flowers. Suppose the true
zloy xaker [14]

Answer:

The probability that the sample proportion will differ from the population proportion by greater than 0.03 is 0.009.

Step-by-step explanation:

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

 \mu_{\hat p}=p

The standard deviation of this sampling distribution of sample proportion is:

 \sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}

As the sample size is large, i.e. <em>n</em> = 492 > 30, the central limit theorem can be used to approximate the sampling distribution of sample proportion by the normal distribution.

The mean and standard deviation of the sampling distribution of sample proportion are:

\mu_{\hat p}=p=0.07\\\\\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.07(1-0.07)}{492}}=0.012

Compute the probability that the sample proportion will differ from the population proportion by greater than 0.03 as follows:

P(|\hat p-p|>0.03)=P(|\frac{\hat p-p}{\sigma_{\hat p}}|>\frac{0.03}{0.012})

                           =P(|Z|>2.61)\\\\=1-P(|Z|\leq 2.61)\\\\=1-P(-2.61\leq Z\leq 2.61)\\\\=1-[P(Z\leq 2.61)-P(Z\leq -2.61)]\\\\=1-0.9955+0.0045\\\\=0.0090

Thus, the probability that the sample proportion will differ from the population proportion by greater than 0.03 is 0.009.

5 0
3 years ago
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Talja [164]

Answer:

30.42 (if rounded to the tenths place)

Step-by-step explanation:

4 0
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GCF of 9ab^2 and 6bc^2
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For this case we have that by definition, the GCF (Greatest Common Factor) is the largest integer that divides the numbers.

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We find the factors of 9 and 6:

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Thus, the largest number that divides 9 and 6 is 3

It is also observed that "b" is the common variable of both expressions

Therefore, the GCF of the expressions is:

3b

Answer:

3b

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3 years ago
Simplify 6^7/6^5 in index form
Oksanka [162]

Answer:

6²

Step-by-step explanation:

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= 6^{(7-5)}

= 6²

6 0
3 years ago
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