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Drupady [299]
3 years ago
7

The 154 tenth-graders at Wilson High School were polled on whether they enjoyed their algebra or geometry course more. The resul

ts are shown below. Algebra: 34 female, 33 male Geometry: 40 female, 47 male Use the drop-down menus to answer the questions. What is the probability that a randomly chosen tenth-grader is male? What is the probability that a randomly chosen tenth-grader is male given that the tenth-grader prefers geometry? Are the events “male” and “geometry” independent?
Mathematics
2 answers:
wolverine [178]3 years ago
8 0

Answer: 80/154

47/87

No, P(male)does not equal P(male | geometry)

Step-by-step explanation:

WITCHER [35]3 years ago
7 0

Answer:

1) D (80/154)  2) B (47/87) 3) A

Step-by-step explanation:

Right on edge.

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Turner has 6 pounds of pasta.Each Time he makes dinner he uses 3/4 pound of pasta.How many dinners can he make?
gtnhenbr [62]
3/4 is equal to 0.75

So, 6 divided by 0.75 which gives you 8
or it could also be written as 6 divided by 3/4 which is also 8..

SO in summary, Turner can make 8 dinners
7 0
4 years ago
Read 2 more answers
What is the area of one trapezoidal face of the figure?
Arturiano [62]
The area of a trapezoid, A, is the average of the lengths of the bases (B and b) multiplied by the height, h.

A = \dfrac{(B + b)h}{2}

A = \dfrac{(3~in. + 1~in.) \times 1~in.}{2}

A = \dfrac{4~in. \times 1~in.}{2}

A = \dfrac{4~in.^2}{2}

A = 2~in.^2
3 0
4 years ago
6.6. Using the extended Euclidean algorithm, compute the greatest common divisor and the parameters s,t of 1. 198 and 243 2. 181
Snowcat [4.5K]

Answer:

1) The gcd is 9

9 = 9*243-11*198

2) The gcd is 17

17 = -36*3587+71*1819

Step-by-step explanation:

1) First, we divide the greater number with the smallest:

243/198 = 1.227....

The whole value is 1, and the remainder is243-1*198 = 45

Now we take the second number, 198 and 45 and repeat the same process:

198/45 = 4.4

The whole part is 4

the remainder is

198 - 4*45 = 18

Now we take 45 and 18 and repeat the process

45/18 = 2.5

the whole part is 2, the remainder is 45-2*18 = 9

Now,

18/9 = 2 is a whole number, so we stop in 9, which is the gcd.

How we find s,t?

We have to start from 9 and go upwards, replacing in bigger numbers (used in our algorithm) if possible

9 = 45-2*18

Now, we replace 18, using 18 = 198-4*45

9 = 45-2*18 = 45- 2*(198-4*45) = 9*45 - 2*198

Now, time to replace 45, using 45 = 243-198

9 = 9*45-2*198 = 9*(243-198) - 2*198 = 9*243 - 11*198

If we make the computation 9*243-11*198 = 2187-2178 = 9

Thus, the gcd is 9 and the parameters are 9 for 243 and -11 for 198.

2)

Lets divide 3587 with 1819

3587/1819 = 1.971...

The whole part is 1, the remainder is

3587-1*1819 = 1768

Now, its the turn for 1819 and 1768

clearly, the whole part oof the division will be 1, since ther are similar numbers. The remainder is 1819-1768 = 51

Now, lets continue with 1768 and 51

1768/51 = 34.66666

The whole part is 34, the remainder is

1768-34*51 = 34

Now, between 51 and 34:

The whole part of 51/34 is 1 and the remainder is 51-34 = 17

And between 34 and 17:

34/17 = 2, which is a whole number. So we stop in 17.

The gcd is 17, lets find now the parameters. We start by replacing 17

17 = 51 - 1*34

Now 34: 34 = 1768-34*51

51-34 = 51-(1768-34*51) = 35*51-1768

Now, we replace 51 = 1819-1768:

35*51-1768 = 35*(1819-1768) - 1768 = 35*1819-36*1768

And last, we replace 1768 with 3587-1819

35*1819-36*1768 = 35*1819-36*(3587-1819) = 71*1819 - 36*3587

So, the parameters for 3587 and 1819 are -36 and 71 respectively and the gcd is 17.

Lets check:

-36*3587+71*1819 = -129132+129149 = 17

3 0
4 years ago
What do all points that lie on the y-axis have in common in terms of their coordinates?
vitfil [10]
For all points that lie on the y-axis, the x-coordinate is zero.
5 0
2 years ago
Find the value of x and y that make the quadrilateral
vitfil [10]

The quadrilateral have equal opposite sides, for example:

Then, (4x + 6) must be equal to (7x - 3), and (4y - 3) is equal to (3y + 1), therefore

4x+6=7x-3

We can solve that equation for x

\begin{gathered} 4x+6=7x-3 \\  \\ 3x=9 \\  \\ x=\frac{9}{3}=3 \end{gathered}

Hence, x = 3. Now let's solve the other equation

\begin{gathered} 4y-3=3y+1 \\  \\ y=4 \end{gathered}

Then the value of y is 4.

Final answers:

x = 3

y = 4

4 0
1 year ago
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