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ki77a [65]
3 years ago
9

The equations were multiplied by constants and added together to determine that the value of x in the system of equations is –20

. One-fifth x minus one-third y = negative 1 Negative three-fourths x + one-third y = 12 What is the value of y? –15 –9 9 15
Mathematics
1 answer:
Misha Larkins [42]3 years ago
8 0

Answer:

Step-by-step explanation:

Given:

1. 1/5x - 1/3y = -1

2. -3/4x +1/3y = 12

Multiplying equation 1 by 15 and equation 2 by 12

3. 3x - 5y = -15

4. -9x + 4y = 144

and then Solving both equations simultaneously, since x = -20 as stated in the question and by confirmation,

Using equation 3 or 4 to solve for y,

3(-20) - 5y = -15

-5y = 60 - 15

y = 45/-5

= -9

y = -9

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The sum of 2 fractions is 5/6. Their difference is 1/2. Their least common denominator is 6. The denominator of one is twice the
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Answer:

Step-by-step explanation:

Alright, lets get started.

Suppose the first fraction is : \frac{a}{b}

Suppose the second fraction is : \frac{c}{d}

The sum of both fraction is given as : \frac{5}{6}

\frac{a}{b}+\frac{c}{d}=\frac{5}{6}    .......................equation (1)

The difference of both fraction is given as : \frac{1}{2}

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Adding equation (1) and equation (2)

\frac{c}{d} \ will  \ be \ cancelled

\frac{2a}{b}=\frac{5}{6}+\frac{1}{2}

making common denominator

\frac{2a}{b}=\frac{5}{6}+ \frac{3}{6}

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Hence,

\frac{a}{b}=\frac{2}{3}

Plugging the value of \frac{a}{b} in equation (1)

\frac{2}{3}+\frac{c}{d}=\frac{5}{6}

Subtracting \frac{2}{3} in both sides

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Hope it will help :)

7 0
3 years ago
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Answer:

781.25

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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