Question

What is the logarithmic form of the equation e4x ≈ 2981?

Answer 1

Since it has e we can use the natural long so it would be
 in2981=4x

Answer 2

Answer:

$\ln(2981)=4x$

Step-by-step explanation:

The given equation is $e^{4x}\approx2981$

We can use the relation between logarithmic and exponential function.

$\text{If }y=b^x\text{ then }x=\log_b(y)$

Here,

b = e

x = 4x

y = 2981

Thus, using the above relation, we can write

$e^{4x}\approx2981\\\\\log_e(2981)=4x$

We know $\log_e(2981)=\ln(2981)$

Hence, we have

$e^{4x}\approx2981\\\\\ln(2981)=4x$