Complete question :
The temperature at 5:00 a.m. was –6 °F. By 3:00 p.m., the temperature had risen to a high of 36 °F. If the temperature at 8:00 p.m. decreased from the high by the change in temperature in Fahrenheit degrees from 5:00 a.m. to 3:00 p.m., what was the temperature at 8:00 p.m.?
Answer:
-6°F
Step-by-step explanation:
Temperature at 5am (t1) = - 6°F
Temperature at 3pm (t2) = 36°F
Change in temperature, between 5am and 3pm:
(t2 - t1) = (36 - (-6)) = (36 + 6) = 42°F
Hence, temperature at 8:00 pm:
High temperature - change in temperature between (5am - 3pm)
36°F - 42°F = - 6°F
K=am+3mx
K=m(a+3x)
m=K/(a+3x)
Answer: m=K/(a+3x)
9 dollars represents 90% of the cost. Divide 9 by 0.90 to get the original price, 10 dollars
Answer:
Option (2). x = 20°
Step-by-step explanation:
In the figure attached,
ΔABC is an equilateral triangle.
By the property of equilateral triangle, all sides of the triangle are equal and measure of all angles of the triangle is 60°.
By this property,
m∠B = 60°
and y = 46 - 16 = 30
By applying Sine rule in ΔBCD,
sin(∠CBD) = 
= 0.6423
m∠CBD = 39.96
≈ 40°
m∠ABD = 60° - 40°
= 20°
Therefore, Option (2). 20° will be the answer.
Answer:
The inverse of the function is ±sqrt( (x+4)/2
Step-by-step explanation:
Set the function equal to y
y = 2x^2 -4
Exchange x and y
x = 2y^2 -4
Solve for y
Add 4 to each side
x+4 = 2y^2 -4+4
x+4 = 2y^2
Divide each side by 2
(x+4)/2 = 2/2y^2
(x+4)/2 = y^2
Take the square root of each side
±sqrt( (x+4)/2 )= sqrt(y^2)
±sqrt( (x+4)/2 )= y
The inverse of the function is ±sqrt( (x+4)/2
