(n*3)+6-(n*2)=n+3
3n+6-2n=n+3
3n-2n-n=3-6 every n on the left and free numbers on the right
0=-3
contradiction, there are no solution
The height of the building to the nearest tenth of a meter is; 13 m
<h3>How to make use of Cosine Rule?</h3>
The slant line from the top of Trevor's head to the base of the building is gotten from Pythagoras theorem;
15/x = sin 36°
x = 15/sin 36
x = 25.52 m
Angle between that slant line and base of building is;
90 - tan⁻¹(1.5/14) = θ
θ = 83.88°
Remaining angle of the bigger triangle is;
180 - (36 + 83.88) = 60.12°
Thus, if the height of the building is h, then;
h/sin 36 = 25.52/sin 60.12
h = 13 m
Read more about Cosine Rule at; brainly.com/question/4372174
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∫(t = 2 to 3) t^3 dt
= (1/4)t^4 {for t = 2 to 3}
= 65/4.
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∫(t = 2 to 3) t √(t - 2) dt
= ∫(u = 0 to 1) (u + 2) √u du, letting u = t - 2
= ∫(u = 0 to 1) (u^(3/2) + 2u^(1/2)) du
= [(2/5) u^(5/2) + (4/3) u^(3/2)] {for u = 0 to 1}
= 26/15.
----
For the k-entry, use integration by parts with
u = t, dv = sin(πt) dt
du = 1 dt, v = (-1/π) cos(πt).
So, ∫(t = 2 to 3) t sin(πt) dt
= (-1/π) t cos(πt) {for t = 2 to 3} - ∫(t = 2 to 3) (-1/π) cos(πt) dt
= (-1/π) (3 * -1 - 2 * 1) + [(1/π^2) sin(πt) {for t = 2 to 3}]
= 5/π + 0
= 5/π.
Therefore,
∫(t = 2 to 3) <t^3, t√(t - 2), t sin(πt)> dt = <65/4, 26/15, 5/π>.
The formula for volume of a hemisphere is: V = 2/3 * π * r³
Volume = 2/3 x 3.14 x 150^3
Volume = 7,065,000 cubic feet.
Multiply the cost per cubic foot by the volume:
7,065,000 x 0.05 = 353,250
The total cost was $353,250
