All categories

3 years ago

What is the sum of the exterior angle measures, one at each vertex, of a convex polygon with 11 sides?

Mathematics

2 answers:

Dennis_Churaev [7]3 years ago

8 0

The sum (for all polygons) of the exterior angles are 360. So, 360/11 is 32.72

hope this helps!

elena-s [515]3 years ago

3 0

The answer is 360. All exterior angles of polygons equal 360°

(I had this question and got it correct)

Hope you guys find this helpful.

You might be interested in

What is the probability of choosing a square

Ghella [55]

Answer:

I hope this answers your questions.

Explanation:

Divide the number of events by the number of possible outcomes. This will give us the probability of a single event occurring.

I hope this helps!!!!

4 0

3 years ago

Find the coordinates of the circumcenter of the triangle below

Lena [83]

(2,2) (6,2) (6,8) Hope this helps I’m pretty sure this is correct :)

6 0

3 years ago

What is the length of BC , rounded to the nearest tenth?

Arte-miy333 [17]

Step $1$

In the right triangle ADB

Find the length of the segment AB

Applying the Pythagorean Theorem

$AB^{2} =AD^{2}+BD^{2}$

we have

$AD=5\ units\\BD=12\ units$

substitute the values

$AB^{2}=5^{2}+12^{2}$

$AB^{2}=169$

$AB=13\ units$

Step $2$

In the right triangle ADB

Find the cosine of the angle BAD

we know that

$cos(BAD)=\frac{adjacent\ side }{hypotenuse}=\frac{AD}{AB}=\frac{5}{13}$

Step $3$

In the right triangle ABC

Find the length of the segment AC

we know that

$cos(BAC)=cos (BAD)=\frac{5}{13}$

$cos(BAC)=\frac{adjacent\ side }{hypotenuse}=\frac{AB}{AC}$

$\frac{5}{13}=\frac{AB}{AC}$

$\frac{5}{13}=\frac{13}{AC}$

solve for AC

$AC=(13*13)/5=33.8\ units$

Step $4$

Find the length of the segment DC

we know that

$DC=AC-AD$

we have

$AC=33.8\ units$

$AD=5\ units$

substitute the values

$DC=33.8\ units-5\ units$

$DC=28.8\ units$

Step $5$

Find the length of the segment BC

In the right triangle BDC

Applying the Pythagorean Theorem

$BC^{2} =BD^{2}+DC^{2}$

we have

$BD=12\ units\\DC=28.8\ units$

substitute the values

$BC^{2}=12^{2}+28.8^{2}$

$BC^{2}=973.44$

$BC=31.2\ units$

therefore

the answer is

$BC=31.2\ units$

8 0

3 years ago

Read 2 more answers

Find the area of the triangle

kupik [55]

Area = 1/2 * base * height
= 1/2 * 20 * 6
= 1/2 * 120
= 60 ft^2

6 0

3 years ago

Expand and simplify <img src="https://tex.z-dn.net/?f=%20%283x-2%29%5E%7B2%7D%20" id="TexFormula1" title=" (3x-2)^{2} " alt=" (3

Rus_ich [418]

You can just 1) multiply the binomial by itself, or you can use 2) the square of a binomial pattern. I'll show it to you both ways.

1) Multiply the binomial by itself.

(3x - 2)^2 = (3x - 2)(3x - 2) =

Multiply every term of the first binomial by every term of the second binomial, then collect like terms. (This is often called using FOIL.)

= 9x^2 - 6x - 6x + 4

= 9x^2 - 12x + 4

2) Use the square of a binomial pattern

The square of a binomial is

(a - b)^2 = a^2 - 2ab - b^2

a^2 is the square of the first term.
b^2 is the square of the second term.
-2ab is the product of the two terms and 2.

You have

(3x - 2)^2,
where the first term is 3x, and the second term is -2

square the first term: 9x^2
square the last term: 4
the product of the terms and 2 is: -12x

Put it all together, and you get

9x^2 - 12x + 4

just like we got above with the other method.

7 0

3 years ago