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MatroZZZ [7]
2 years ago
12

Given f (x) = -3x + 4, solve for x when f (x) = 1

Mathematics
1 answer:
Solnce55 [7]2 years ago
8 0

Answer:

1

Step-by-step explanation:

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Jason and Jill or two students in mr. White's math class. On the last 5 quizzes Jason scored an 80 90 95 85 and 70. Jill scored
Mrac [35]

Jason's scores : 80 90 95 85 70 and

Jill's score : 70 75 90 100 95.

Mean of Jason's scores = \frac{80 + 90 + 95 + 85 + 70}{5}=\frac{420}{5}=84.

Mean of Jill's scores = \frac{70+75+90+100+95}{5}=\frac{430}{5}=86

Now, in order to find the mean absolute deviation, need to find the difference of each score from means.

<u>Mean absolute deviation for Jason's scores.</u>        

|84-80| = 4

|84-90| = 6

|84-95| = 9

|84-85| = 1

|84-70|= 14

\frac{4+6+9+1+14}{5}=\frac{34}{5}=6.8

<u>Mean absolute deviation for Jill's scores</u>

|86-70| = 16

|86-75| = 11

|86-90| = 4

|86-100| = 14

|86-95|= 9

\frac{16+11+4+14+9}{5}=\frac{54}{5}=10.8

Jill got average quiz score 86 and Jason got 84.

Therefore, Jill got better quiz average.

Also, the mean absolute deviation for Jason scores is less that is 6.8 than 10.8.

Therefore, Jason got more consistent grades.

8 0
3 years ago
I need someone to help me do this, see attached documents for the questions
Brilliant_brown [7]

Answer:

<u><em>1.) 20.2</em></u>

Step-by-step explanation:

1.) You need to use the distance formula:

d=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Find the distance of A to B first:

(-2,2)(3,2)\\\\\sqrt{(3+2)^2+(2-2)^2}\\\\\sqrt{(5)^2+(0)^2}\\\\\sqrt{25} =5

B to C:

(3,2)(-1,-5)\\\\\sqrt{(-1-3)^2+(-5-2)^2}\\\\\sqrt{(-4)^2+(-7)^2}\\\\\sqrt{16+49}\\\\\sqrt{65} =8.06=8.1

C to A:

(-1,-5)(-2,2)\\\\\sqrt{(-2+1)^2+(2+5)^2}\\\\\sqrt{(-1)^2+(7)^2}\\\\\sqrt{1+49}\\\\\sqrt{50}=7.07=7.1

Add distances to find the perimeter:

5+8.1+7.1=20.2

2.) Part A:

You need to use the mid-point formula:

midpoint=(\frac{x_{1}+x_{2}}{2} ,\frac{y_{1}+y_{2}}{2} )

(3,2)(7,11)\\\\(\frac{3+7}{2},\frac{2+11}{2})\\\\(\frac{10}{2},\frac{13}{2})\\\\m=(  5,6.5)

Part B:

1. Use the slope-intercept formula:

y=mx+b

M as the slope, b the y-intercept.

Find the slope of the two points A and B using the slope formula:

m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} =\frac{rise}{run}

Insert slope as m into equation.

Take point A as coordinates (x,y) and insert into the equation. Solve for the intercept, b:

(y)=m(x)+b

Insert the value of b into the equation.

2.  Use the mid-point coordinate. Take the slope.

If you need to find the perpendicular bisector, you will take the negative reciprocal of the slope. Switch the sign and flip it. Ex:

\frac{1}{2} =-\frac{2}{1}=-2\\

Insert the new slope into the slope-intercept equation as m.

Take the mid-point coordinate as (x,y) and insert into the equation with the new points. Solve for b.

Insert the value of b.

4 0
4 years ago
9/3 *[(18-10)-2^2]<br><br><br>36<br><br>12<br><br>0.25<br><br>0.75
poizon [28]

Answer:

12

Step-by-step explanation:

Use the PEMDAS

there is a parenthesis and exponents

9/3{(8) - 4)}

Multiply and divide 9/3= 3

Also subtract 8-4 = 4

3{8-4}

3(4)= 12

5 0
3 years ago
!ASAP!<br> Please answer soon
yan [13]

Answer:

1. Pyramid= ll+l^2  2. Rectangular prism= 2 lw+2lh+2wh 3. Cylinder= 2pi pi rh+2pi pi r^2  4.Triangular Prism= 2 B + Ph  5. Cone= Pi rl+ pi r^2

Step-by-step explanation:

Pretty sure this is your answer. Hope it helps!

6 0
2 years ago
Factoring special case<br>factor each completely<br>9x2-1 ​
Dafna1 [17]
Answer should be 17.
7 0
3 years ago
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