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MArishka [77]
3 years ago
12

Evelyn is making a candy that contains 25% dark chocolate and the rest milk chocolate. The candy has 3 pounds of milk chocolate.

Mathematics
1 answer:
Vitek1552 [10]3 years ago
4 0

<em>Part A: </em>

Let c represent the total amount of chocolate there is in lbs.

c = 0.25c + 0.75c

<em>Part B: </em>

0.75c represents milk chocolate, and we know that there are 3 lbs of milk chocolate, so you can replace the 0.75c with 3 (representing 3 lbs):

c = 0.25c + 3

Divide all the terms by c:

1 = 0.25 + 3/c

Subtract 0.25 from both sides to combine the like terms:

0.75 = 3/c

Multiply all the terms by c to make the equation easier to work with:

0.75c = 3

Divide both sides by 0.75 to isolate the c and find the total amount of chocolate in pounds.

c = 4

Substitute c for 4 in the term that defines dark chocolate (which was 0.25c)

0.25(4) = 1 pound

Therefore, there was exactly 1 pound of dark chocolate present in the chocolate.

This makes sense, as 1 pound of dark chocolate + 3 pounds of milk chocolate = 4 pounds of chocolate in total, and 1 is 25% of 4 and 3 is 75% of 4.


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Answer: The tank which has 3 m side.

Step-by-step explanation: A cube is a form that has equal sides. To calculate the volume of it, multiply all three sides:

V = length*width*height

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V = s³

One tank has a 3 m side, so its volume is:

V = 3³

V = 27 m³

The other has half of the first one side, then s = \frac{3}{2} and volume will be:

V = (\frac{3}{2})^{3}

V = \frac{27}{8} m³

As you can see, the volume of the second tank is \frac{1}{8} smaller than the first one. Therefore, the tank which has 3 m side can store more water than the  tank with side measuring half of the first.

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3 years ago
Prove that if x is irrational, then 1/x is irrational
ozzi

Proof by contradiction.

Let assume that when x is an irrational number, then \dfrac{1}{x} is a rational number.

If \dfrac{1}{x} is a rational number, then it can be expressed as a fraction \dfrac{a}{b} where a,b\in\mathbb{Z}.

\dfrac{1}{x}=\dfrac{a}{b} \Rightarrow x=\dfrac{b}{a}

Since a,b\in\mathbb{Z}, the number x=\dfrac{b}{a} is also a rational number. But this contardicts our initial assumption that x is an irrational number. Therefore \dfrac{1}{x} must be an irrational number.

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A machine used to fill​ gallon-sized paint cans is regulated so that the amount of paint dispensed has a mean of ounces and a st
11111nata11111 [884]

Complete question is;

A machine used to fill gallon-sized paint cans is regulated so that the amount of paint dispensed has a mean of 128 ounces and a standard deviation of 0.20 ounce. You randomly select 35 cans and carefully measure the contents. The sample mean of the cans is 127.9 ounces. Does the machine need to be? reset? Explain your reasoning.

(yes/no)?, it is (very unlikely/ likely) that you would have randomly sampled 35 cans with a mean equal to 127.9 ?ounces, because it (lies/ does not lie) within the range of a usual? event, namely within (1 standard deviation, 2 standard deviations 3 standard deviations) of the mean of the sample means.

Answer:

Yes, we should reset the machine because it is unusual to have a mean equal to 127.9 from a random sample of 35 as the mean of 127.9 doesn't fall within range of a usual event with 2 standard deviations of the mean of the sample means.

Step-by-step explanation:

We are given;

Mean: μ = 128

Standard deviation; σ = 0.2

n = 35

Now, formula for standard error of mean is given as;

se = σ/√n

se = 0.2/√35

se = 0.0338

Normally, the range of values should be within 2 standard deviations of mean. In this case, normal range of values will be;

μ ± 2se = 128 ± 0.0338

This gives; 127.9662, 128.0338

So, Yes, we should reset the machine because it is unusual to have a mean equal to 127.9 from a random sample of 35 as the mean of 127.9 doesn't fall within range of a usual event with 2 standard deviations of the mean of the sample means.

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3 years ago
In a parallelogram, two sides are each length 12, and the perimeter is 36, what is the length of the remaining sides?
tankabanditka [31]
P=2a+2b
P=36
a=12
36=2*12+2b
36=24+2b
36-24=2b
12=2b
b=6
So, the length of the remaining sides is 6 each.
5 0
3 years ago
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