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Sergeu [11.5K]
3 years ago
13

In a Northwest Washington County, speeding fines are determined by the formula

Mathematics
1 answer:
AlekseyPX3 years ago
3 0

The person was speeding at 93 miles per hour.

Step-by-step explanation:

  • Step 1: Given the equation to find speeding fine F = 7(s - 65) + 70
  • Step 2: Substitute given details in the equation and find s. F = $266

⇒ 266 = 7(s - 65) + 70

⇒ 266 = 7s - 455 + 70

⇒ 266 = 7s - 385

⇒ 651 = 7s

⇒ s = 651/7 = 93

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If a triangle has a base of 36 and a height of 15, what would the area be.​
Bad White [126]

Answer:

270 units squared

Step-by-step explanation:

The formula to find the area of a triangle is 1/2 base times height

The base is 36 and the height is 15 so the answer would be equal to

1/2(36 * 15)

36 * 15 = 540

1/2(540) = 270

The answer simplifies to 270 units^2 because this is area and area is always squared

3 0
3 years ago
Domain is the __of an order pair, which is known as the __ value.
valentinak56 [21]

Answer:

first coordinates

x

Step-by-step explanation:

5 0
3 years ago
Conjugate/Rational Number?
hram777 [196]

Answer:

1)  \dfrac{2}{\sqrt{5} }  = \dfrac{2 \cdot \sqrt{5} }{5}

2)  -\dfrac{5}{\sqrt{3} } = -\dfrac{5 \cdot \sqrt{3} }{3}

3)  \dfrac{\sqrt{2} + \sqrt{5}  }{\sqrt{10} } =\dfrac{\sqrt{5}  }{5} + \dfrac{ \sqrt{2}  }{2}

4)  \dfrac{3 + \sqrt{2} }{\sqrt{3} } \times \dfrac{\sqrt{3} }{\sqrt{3} } = \sqrt{3} + \dfrac{\sqrt{6} }{3}

5)  \dfrac{\sqrt{3} }{\sqrt{5} + \sqrt{2}  }= \dfrac{\sqrt{15} - \sqrt{6} }{3}

Step-by-step explanation:

The rationalization of the denominator of the surds are found as follows;

1) \dfrac{2}{\sqrt{5} }

\dfrac{2}{\sqrt{5} } \times \dfrac{\sqrt{5} }{\sqrt{5} } = \dfrac{2 \cdot \sqrt{5} }{5}

\dfrac{2}{\sqrt{5} }  = \dfrac{2 \cdot \sqrt{5} }{5}

2) -\dfrac{5}{\sqrt{3} }

-\dfrac{5}{\sqrt{3} } \times \dfrac{\sqrt{3} }{\sqrt{3} } = -\dfrac{5 \cdot \sqrt{3} }{3}

-\dfrac{5}{\sqrt{3} } = -\dfrac{5 \cdot \sqrt{3} }{3}

3) \dfrac{\sqrt{2} + \sqrt{5}  }{\sqrt{10} }

\dfrac{\sqrt{2} + \sqrt{5}  }{\sqrt{10} } \times \dfrac{ \sqrt{10}  }{\sqrt{10} } = \dfrac{\sqrt{20} + \sqrt{50}  }{10 } = \dfrac{2\cdot \sqrt{5} + 5 \cdot \sqrt{2}  }{10} = \dfrac{\sqrt{5}  }{5} + \dfrac{ \sqrt{2}  }{2}

\dfrac{\sqrt{2} + \sqrt{5}  }{\sqrt{10} } =\dfrac{\sqrt{5}  }{5} + \dfrac{ \sqrt{2}  }{2}

4) \dfrac{3 + \sqrt{2} }{\sqrt{3} }

\dfrac{3 + \sqrt{2} }{\sqrt{3} } \times \dfrac{\sqrt{3} }{\sqrt{3} } = \dfrac{3 \cdot \sqrt{3}+\sqrt{6}  }{3 } = \sqrt{3} + \dfrac{\sqrt{6} }{3}

\dfrac{3 + \sqrt{2} }{\sqrt{3} } \times \dfrac{\sqrt{3} }{\sqrt{3} } = \sqrt{3} + \dfrac{\sqrt{6} }{3}

5) \dfrac{\sqrt{3} }{\sqrt{5} + \sqrt{2}  }

\dfrac{\sqrt{3} }{\sqrt{5} + \sqrt{2}  } = \dfrac{\sqrt{5} - \sqrt{2} }{\sqrt{5} - \sqrt{2} }  = \dfrac{\sqrt{15} -\sqrt{6} }{5 - 2} = \dfrac{\sqrt{15} - \sqrt{6} }{3}

\dfrac{\sqrt{3} }{\sqrt{5} + \sqrt{2}  }= \dfrac{\sqrt{15} - \sqrt{6} }{3}

6) \dfrac{\sqrt{7} }{\sqrt{3} - \sqrt{5}  }

\dfrac{\sqrt{7} }{\sqrt{3} - \sqrt{5}  } \times \dfrac{\sqrt{3} + \sqrt{5}}{\sqrt{3} + \sqrt{5}}  = \dfrac{\sqrt{21} + \sqrt{35}}{{3} + {5}} = \dfrac{\sqrt{21} + \sqrt{35}}{8}

\dfrac{\sqrt{7} }{\sqrt{3} - \sqrt{5}  } \times \dfrac{\sqrt{3} + \sqrt{5}}{\sqrt{3} + \sqrt{5}}  =\dfrac{\sqrt{21} + \sqrt{35}}{8}

8 0
3 years ago
Can you help me with this question?
RoseWind [281]

Answer:

Reason SAS postulate

Step-by-step explanation:

The two triangles must be congruent.

Reason: SAS postulate

6 0
2 years ago
PLZ help 50 points and brainleist Which expression shows the result of applying the distributive property to −2(1/3 x− 1/5)
CaHeK987 [17]

Answer:

the answer is A

Step-by-step explanation:

5 0
3 years ago
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