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Sergeu [11.5K]
3 years ago
13

In a Northwest Washington County, speeding fines are determined by the formula

Mathematics
1 answer:
AlekseyPX3 years ago
3 0

The person was speeding at 93 miles per hour.

Step-by-step explanation:

  • Step 1: Given the equation to find speeding fine F = 7(s - 65) + 70
  • Step 2: Substitute given details in the equation and find s. F = $266

⇒ 266 = 7(s - 65) + 70

⇒ 266 = 7s - 455 + 70

⇒ 266 = 7s - 385

⇒ 651 = 7s

⇒ s = 651/7 = 93

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When 0.3(4x – 8) – 0.5(–2.4x + 4) is simplified, what is the resulting expressions
lisabon 2012 [21]

Answer:

2.4x-4.4

Step-by-step explanation:

Given the following question:

0.3(4x-8)-0.5(-2.4x+4)

To simplify the expression, we are going to need to rewrite the expression by expanding the terms and then solve by using the distributive property. Then we combine like terms in till the expression can no longer be simplified to find our answer.

0.3(4x-8)-0.5(-2.4x+4)
0.3(4x-8)
0.3\times4=1.2x
0.3\times4=2.4
1.2x-1.2-0.5(-2.4x+4)
-0.5(-2.4x+4)
-0.5\times-2.4=1.2
-0.5\times4=-2
1.2-2
1.2x-2.4+1.2x-2
1.2+1.2=2.4x
-2.4+-2=-4.4
=2.4x-4.4

Your answer is "2.4x - 4.4."

Hope this helps.

6 0
3 years ago
Bad gums may mean a bad heart. Researchers discovered that 79% of people who have suffered a heart attack had periodontal diseas
zysi [14]

Answer:

(A) 0.297

(B) 0.595

Step-by-step explanation:

Let,

H = a person who suffered from a heart attack

G = a person has the periodontal disease.

Given:

P (G|H) = 0.79, P(G|H') = 0.33 and P (H) = 0.15

Compute the probability that a person has the periodontal disease as follows:

P(G)=P(G|H)P(H)+P(G|H')P(H')\\=P(G|H)P(H)+P(G|H')(1-P(H))\\=(0.79\times0.15)+(0.33\times(1-0.15))\\=0.399

(A)

The probability that a person had periodontal disease, what is the probability that he or she will have a heart attack is:

P(H|G)=\frac{P(G|H)P(H)}{P(G)}\\=\frac{0.79\times0.15}{0.399} \\=0.29699\\\approx0.297

Thus, the probability that a person had periodontal disease, what is the probability that he or she will have a heart attack is 0.297.

(B)

Now if the probability of a person having a heart attack is, P (H) = 0.38.

Compute the probability that a person has the periodontal disease as follows:

P(G)=P(G|H)P(H)+P(G|H')P(H')\\=P(G|H)P(H)+P(G|H')(1-P(H))\\=(0.79\times0.38)+(0.33\times(1-0.38))\\=0.5048

Compute the probability of a person having a heart attack given that he or she has the disease:

P(H|G)=\frac{P(G|H)P(H)}{P(G)}\\=\frac{0.79\times0.38}{0.5048}\\ =0.59469\\\approx0.595

The probability of a person having a heart attack given that he or she has the disease is 0.595.

4 0
3 years ago
Please help anyone......
Neko [114]

Answer:

5. is 39 and i don't want to answer the other one sorry:(

Step-by-step explanation:

7 0
3 years ago
40 POINTS!!!!!!!!!!!!!!!!!!!!!!!!!!!!! HELPPPPPPPP!!!
Dmitrij [34]
School to mall - 16 miles
mall  to library - 30 miles

16²+30²=X²
256+900=X²
X²=1156
X=34

16+30=46
hypotenuse = 34
46-34=12
So Mike travel 12 miles more.



5 0
3 years ago
Read 2 more answers
In the diagram, LaTeX: \Delta ABC\cong\Delta DFE
leonid [27]

Answer:

x = 13

y = 8

Step-by-step explanation:

8 0
3 years ago
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