Answer:
(A) 0.297
(B) 0.595
Step-by-step explanation:
Let,
H = a person who suffered from a heart attack
G = a person has the periodontal disease.
Given:
P (G|H) = 0.79, P(G|H') = 0.33 and P (H) = 0.15
Compute the probability that a person has the periodontal disease as follows:

(A)
The probability that a person had periodontal disease, what is the probability that he or she will have a heart attack is:

Thus, the probability that a person had periodontal disease, what is the probability that he or she will have a heart attack is 0.297.
(B)
Now if the probability of a person having a heart attack is, P (H) = 0.38.
Compute the probability that a person has the periodontal disease as follows:

Compute the probability of a person having a heart attack given that he or she has the disease:

The probability of a person having a heart attack given that he or she has the disease is 0.595.
Answer:
5. is 39 and i don't want to answer the other one sorry:(
Step-by-step explanation:
School to mall - 16 miles
mall to library - 30 miles
16²+30²=X²
256+900=X²
X²=1156
X=34
16+30=46
hypotenuse = 34
46-34=12
So Mike travel 12 miles more.
Answer:
x = 13
y = 8
Step-by-step explanation: