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Talja [164]
2 years ago
9

!!!!!!!HELP ASAP!!!!!!!!!

Mathematics
1 answer:
Scrat [10]2 years ago
4 0
7/28 = 4/?
4*28 = 112. (a) = 16
112 ÷ 7 = 16.

7/588 = 4/?
4*588 =2,352. (b) = 336
2,352 ÷ 7 = 336

7/686 = 4/?
4*686 = 2,744. (c) = 392
2,744 ÷ 7 = 392
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Pregón de servicio<br>kjjj​
babunello [35]

Answer:

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Step-by-step explanation:

5 0
3 years ago
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3. Jim invests $3500, compounded annually at 12% for 3 years. What is the total
irga5000 [103]

Answer:

None of the above, it should be $4760

Step-by-step explanation:

First, converting R percent to r a decimal

r = R/100 = 12%/100 = 0.12 per year,

then, solving our equation

I = 3500 × 0.12 × 3 = 1260

I = $ 1,260.00

The simple interest accumulated

on a principal of $ 3,500.00

at a rate of 12% per year

for 3 years is $ 1,260.00

3 0
2 years ago
Why is the answer to this integral's denominator have 1+pi^2
ss7ja [257]

It comes from integrating by parts twice. Let

I = \displaystyle \int e^n \sin(\pi n) \, dn

Recall the IBP formula,

\displaystyle \int u \, dv = uv - \int v \, du

Let

u = \sin(\pi n) \implies du = \pi \cos(\pi n) \, dn

dv = e^n \, dn \implies v = e^n

Then

\displaystyle I = e^n \sin(\pi n) - \pi \int e^n \cos(\pi n) \, dn

Apply IBP once more, with

u = \cos(\pi n) \implies du = -\pi \sin(\pi n) \, dn

dv = e^n \, dn \implies v = e^n

Notice that the ∫ v du term contains the original integral, so that

\displaystyle I = e^n \sin(\pi n) - \pi \left(e^n \cos(\pi n) + \pi \int e^n \sin(\pi n) \, dn\right)

\displaystyle I = \left(\sin(\pi n) - \pi \cos(\pi n)\right) e^n - \pi^2 I

\displaystyle (1 + \pi^2) I = \left(\sin(\pi n) - \pi \cos(\pi n)\right) e^n

\implies \displaystyle I = \frac{\left(\sin(\pi n) - \pi \cos(\pi n)\right) e^n}{1+\pi^2} + C

6 0
2 years ago
PLEASE HELP!!! Write the equation of a line that goes through the point (6, 3) and is perpendicular to the line y = 4x + 1.
Tpy6a [65]

For this case we have that by definition, the equation of a line in the point-slope form is given by:

y-y_ {0} = m (x-x_ {0})

Where:

m: It is the slope of the line and (x_ {0}, y_ {0})is a point through which the line passes.

We have the following equation of the slope-intersection form:

y = 4x + 1

Where the slope is m = 4

By definition, if two lines are perpendicular then the product of their slopes is -1.

Thus, a perpendicular line will have a slope:

m_ {2} = \frac {-1} {m_ {1}}\\m_ {2} = \frac {-1} {4}\\m_ {2} = - \frac {1} {4}

Thus, the equation will be of the form:

y-y_ {0} = - \frac {1} {4} (x-x_ {0})

Finally we substitute the given point and we have:

y-3 = - \frac {1} {4} (x-6)

Answer:

Option B

8 0
3 years ago
Help pls thank you!!!!!!
jasenka [17]

Answer:

relative minimum would be your awnser

4 0
2 years ago
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