Well. I can't see the picture. But it would be decreasing at a rate of 4 so pick a point on the any line move over to the right one, then down four. And for the y intercept the line would intersect the y axis at positive one. Sorry if that's confusing
Answer:
it is given
, angle 2
, angle 3
, converse alternate exterior angles theorem
Step-by-step explanation:
We know that angle 1 is congruent to angle 3 and that line l is parallel to line m because it is <u>given
</u>. We see that <u>
angle 2
</u> is congruent to <u>angle 3</u> by the alternate interior angles theorem. Therefore, angle 1 is congruent to angle 2 by the transitive property. So, we can conclude that lines p and q are parallel by the <u>
converse alternate exterior angles theorem
</u>.
Note that the 2nd equation can be re-written as y=8x-10.
According to the second equation, y=x^2+12x+30.
Equate these two equations to eliminate y:
8x-10 = x^2+12x+30
Group all terms together on the right side. To do this, add -8x+10 to both sides. Then 0 = x^2 +4x +40. You must now solve this quadratic equation for x, if possible. I found that this equation has NO REAL SOLUTIONS, so we must conclude that the given system of equations has NO REAL SOLUTIONS.
If you have a graphing calculator, please graph 8x-10 and x^2+12x+30 on the same screen. You will see two separate graphs that do NOT intersect. This is another way in which to see / conclude that there is NO REAL SOLUTION to this system of equations.
Answer:
6,18
Step-by-step explanation:
Answer:
2x + 20
Step-by-step explanation:
20 + 2x
