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Tcecarenko [31]
3 years ago
5

Wastewater is filling barrels at the rate of 11 quarts per hour. The recycling facility picks up 120 full barrels on each trip,

and each barrel holds 12 quarts of wastewater. How many days are between each pickup? Show your work to receive full credit. (10 points)
Mathematics
1 answer:
dalvyx [7]3 years ago
8 0
(1 h)/(11 qt) * (12 qt)/(1 barrel) * (120 barrels/pickup) * (1 day)/(24 h)
.. = 12*120/(11*24) day/pickup
.. = 5 5/11 days/pickup

120 barrels will be filled every 5 5/11 days. Some trips will be 5 days apart, some trips will be 6 days apart.
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Two lines intersect and one of the angles formed measures 30°. What are the measures of the other angles?
gogolik [260]
My best answer is C.60 and B.90

6 0
2 years ago
How does the value of the digit 2 in the number 32,000 compare with the value of the digit 2 in the number 26,000?
julsineya [31]

Answer:

the second value is ten times higher then the refference one

6 0
3 years ago
Find the volume of a cone with a base diameter of 12 m and a height of 10 m.
dexar [7]

Answer:

=376.8 m^{3}

Step-by-step explanation:

V=nr^{2}  \frac{h}{3}  Where V is the volume , r is the radius and h is the perpendicular height .

r = \frac{12}{2} m=6

h = 10m

n=3.14

v= 3.14 * 6*6 *\frac{10}{3}

=376.8 m^{3}

5 0
2 years ago
Suppose that two openings on an appellate court bench are to be filled from current municipal court judges. The municipal court
Ksju [112]

Answer:

(a)\dfrac{92}{117}

(b)\dfrac{8}{39}

(c)\dfrac{25}{117}

Step-by-step explanation:

Number of Men, n(M)=24

Number of Women, n(W)=3

Total Sample, n(S)=24+3=27

Since you cannot appoint the same person twice, the probabilities are <u>without replacement.</u>

(a)Probability that both appointees are men.

P(MM)=\dfrac{24}{27}X \dfrac{23}{26}=\dfrac{552}{702}\\=\dfrac{92}{117}

(b)Probability that one man and one woman are appointed.

To find the probability that one man and one woman are appointed, this could happen in two ways.

  • A man is appointed first and a woman is appointed next.
  • A woman is appointed first and a man is appointed next.

P(One man and one woman are appointed)=P(MW)+P(WM)

=(\dfrac{24}{27}X \dfrac{3}{26})+(\dfrac{3}{27}X \dfrac{24}{26})\\=\dfrac{72}{702}+\dfrac{72}{702}\\=\dfrac{144}{702}\\=\dfrac{8}{39}

(c)Probability that at least one woman is appointed.

The probability that at least one woman is appointed can occur in three ways.

  • A man is appointed first and a woman is appointed next.
  • A woman is appointed first and a man is appointed next.
  • Two women are appointed

P(at least one woman is appointed)=P(MW)+P(WM)+P(WW)

P(WW)=\dfrac{3}{27}X \dfrac{2}{26}=\dfrac{6}{702}

In Part B, P(MW)+P(WM)=\frac{8}{39}

Therefore:

P(MW)+P(WM)+P(WW)=\dfrac{8}{39}+\dfrac{6}{702}\\$P(at least one woman is appointed)=\dfrac{25}{117}

5 0
3 years ago
(9.70 x 10^6) + (8.3 x 10^5)=​
nexus9112 [7]

Answer:

1.053  *10 ^7

Hope this helps, you can look it up on google by the way ^^

5 0
2 years ago
Read 2 more answers
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