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4 years ago

14

What is the slope of the graph below?

2 answers:

Mariana [72]4 years ago

6 0

The slope of this graph is -1.

I determined this by using the equation slope= rise/run. In this case, the rise is one and the run is one. This means that the slope is one. Additionally, I notice that the slope is a negative slope which is how I got -1.

You can also use the equation slope = (y2 - y1) all over (x2 - x1). You can do this by getting to ordered pairs from the graph. I took (0,3) and (3,0). So, My equation would be 3-0 all over 0-3. This comes out to 1/-1, which proves the slope is -1.

So again, your answer is the slope is -1.

Hope this helps :)

son4ous [18]4 years ago

3 0

Answer:

It is negative 1.

-1/1

Give me brainliest please!!

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Marian horneó 111 galletas para vender. De las cuales 2/3 les puse glaseado y a las restantes chocolate. Cada galleta de chocola

Svetlanka [38]

Answer:

$647.50

Step-by-step explanation:

111 x 2/3 = 74

111 x 1/3 = 37

$4.50 x 37 = $166.50

$6.50 x 74 = $481

$481 + $166.50 =

$647.50

¡Espero que ayude!

6 0

3 years ago

Read 2 more answers

Find the missing term (x^12)^5 x (x^-2)^9 x what =(x^40)^5

Annette [7]

Answer:

$x^{158}$

Step-by-step explanation:

We are given,

$(x^{12} )^{5} \times (x^{-2} )^{9} \times y = (x^{40} )^{5}$ .

It is required to find the value of y.

Now, on simplifying above equation, we get,

$x^{60} \times x^{-18} \times y = x^{200}$

i.e. $x^{42} \times y = x^{200}$

i.e. $y = x^{200} \times x^{-42}$

i.e. $y = x^{158}$

Hence, the missing term is $x^{158}$ .

3 0

3 years ago

Read 2 more answers

I need help, quick, it's Algebra but super easy, thank you.

horsena [70]

16 - 2(2w + 1) = 8w - 2(8+w)
16 - 4w - 2 = 8w - 16 - 2w
- 4w + 14 = 6w - 16
14 = 10w - 16
30 = 10w
/10 /10
3 = w

I think so lol

3 0

3 years ago

Read 2 more answers

What is the minimum z-score that a data point could have in order to remain in the top 5% of a set of data? Round your answer to

ankoles [38]

Answer:

Hmm i

Step-by-step explanation:

3 0

3 years ago

Which values of c will cause the quadratic equation –x2 3x c = 0 to have no real number solutions? check all that apply.

nika2105 [10]

The given quadratic equation will not have any real solution for c<-9/4.

The given quadratic equation is:

$-x^{2} +3x+c=0$

<h3>What is a quadratic equation?</h3>

Any equation of the form $ax^{2} +bx+c=0$ is called a quadratic equation with a≠0.

In order to have no real solution, the discriminant of a quadratic equation will be less than zero.

$D < 0$

$3^{2} -4(-1)(c) < 0$

$9+4c < 0$

$c < -\frac{9}{4}$

For $c < -\frac{9}{4}$ the given quadratic equation will have no real solutions.

Hence, the given quadratic equation will not have any real solution for c<-9/4.

To get more about quadratic equations visit:

brainly.com/question/1214333

5 0

2 years ago