For the square with side length n, the diagonal measures:
![d = \sqrt{2} *n](https://tex.z-dn.net/?f=d%20%3D%20%5Csqrt%7B2%7D%20%2An)
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How to get the length of the diagonal?</h3>
The sidelength of the square is n, and we want to get the length of the diagonal d.
Notice that the diagonal is the hypotenuse of a right triangle whose catheti measure n.
Then we can use the Pythagorean theorem, which says that the square of the hypotenuse is equal to the sum of the squares of the cathetus;
![d^2 = n^2 + n^2\\\\d^2 = 2n^2\\\\d = \sqrt{2n^2} \\\\d = \sqrt{2}*n](https://tex.z-dn.net/?f=d%5E2%20%3D%20n%5E2%20%2B%20n%5E2%5C%5C%5C%5Cd%5E2%20%3D%202n%5E2%5C%5C%5C%5Cd%20%3D%20%5Csqrt%7B2n%5E2%7D%20%5C%5C%5C%5Cd%20%3D%20%5Csqrt%7B2%7D%2An)
That is the length of the diagonal.
If you want to learn more about right triangles:
brainly.com/question/2217700
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Answer:
f(x) = 3x^2 -21x +36
Step-by-step explanation:
The table gives the x- and y-intercepts, which are sufficient to write the equation in factored form. The x-intercepts of 3 and 4 tell you that factors are (x -3)(x -4). When x=0, this product is (-3)(-4) = 12, but the y-intercept value is 3 times that: 36. So, the factored equation is ...
f(x) = 3(x -3)(x -4)
Multiplying this out, we get ...
f(x) = 3(x^2 -7x +12)
f(x) = 3x^2 -21x +36
what is the domain of the function: {(1, 3); (3, 5); (5, 7); (7, 9)}? a. {1, 3, 5, 7, 9} b. {1, 3, 5, 7} c. {1, 9} d. {3, 5, 7,
Papessa [141]
B. 1, 3, 5, and 7 are x values. Domain is the x value.