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NARA [144]
3 years ago
12

Combine like terms and classify the polynomial by the number of terms. 9xy – 3y + 6xy – 3y A. trinomial B. monomial C. binomial

D. twonomial
Mathematics
2 answers:
Leni [432]3 years ago
8 0
To combine like terms, check if there are any terms just like the first one, and we see 6xy. 9xy + 6xy = 15xy. So that is one term. Now I would see if the second term has any terms like the first one, and we see -3y. So -3y + (-3y), we would get -6y. That means our polynomial is now 15xy - 6y, and because this has two terms, it is a binomial. Hope this helps. Please rate, leave a thanks, and mark a brainliest answer. (Not necessarily mine). Thanks, it really helps!
Basile [38]3 years ago
7 0

Answer: C

Step-by-step explanation:

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All the sides of a hexagon become three times the original length. find the ratio of areas of the new and old hexagons.
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To determine the ratio, we need to know the formula of the area of an hexagon in terms of the length of its sides. We cannot directly conclude that the ratio would be 3, the same as that of the ratio of the lengths of the side, since it may be that the relationship of the area and length is not equal. The area of a hexagon is calculated by the expression:

A = (3√3/2) a^2

So, we let a1 be the length of the original hexagon and a2 be the length of the new hexagon.

A2/A1 = (3√3/2) a2^2 / (3√3/2) a1^2
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Therefore, the ratio of the areas of the new and old hexagon would be 9.
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Cuáles son las condiciones para que sólo se pueda trazar un único rombo ​
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3 years ago
Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule.
lubasha [3.4K]

Answer:

The answer is option C.

<h3>-6, -5 2/5, -4 1/5</h3>

Step-by-step explanation:

The arithmetic sequence is given by

A(n) =  - 6 + (n - 1)( \frac{1}{5} )

where n is the number of terms

<u>For</u><u> </u><u>the</u><u> first</u><u> </u><u>term</u>

n = 1

So we have

A(1) =  - 6 + (1 - 1)( \frac{1}{5} )

=  - 6 + (0)( \frac{1}{5} )

=  - 6

<u>For</u><u> </u><u>the</u><u> </u><u>fou</u><u>rth</u><u> term</u>

n = 4

A(4) =  - 6 + (4 - 1)( \frac{1}{5} )

=  - 6 + (3)( \frac{1}{5} )

=  - 5 \frac{2}{5}

<u>For</u><u> </u><u>the</u><u> </u><u>tenth</u><u> </u><u>term</u>

n = 10

A(10) =  - 6 + (10 - 1)( \frac{1}{5} )

=  - 6 + (9)( \frac{1}{5} )

=  - 4 \frac{1}{5}

Hope this helps you

4 0
3 years ago
Q ,# 13 Graph the function<br>Y = - X + X ^2
GalinKa [24]
We have the following function that is a quadratic function:

y=-x+x^2

So the graph of this function is shown in the figure below. This is a <em>parabola</em> as you can see. The roots of this functions, that is, the x-intercepts are:

y=-x+x^2 \\ y=x(x-1) \\ \\ x_{1}=0 \ and \ x_{2}=1

As you can see in the figure. This function decreases from (-\infty,0.5) and increases from (0.5, \infty)

Finally, another thing we can see from the graph is that the vertex is the point:

V(0.5,-0.25)


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4 years ago
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