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Yuliya22 [10]
3 years ago
13

Find the greatest common factor of 5

Mathematics
2 answers:
VLD [36.1K]3 years ago
6 0

Answer:

the only factors of 5 are 1 and 5, so the greatest common factor of 5 is 5! :)

Step-by-step explanation:


Digiron [165]3 years ago
3 0

5 because 5 is a prime number.

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A machine at a bottling company fills water bottles. the number of bottles filled is proportional to the amount of time the mach
Whitepunk [10]

In the table shown below:

Let N be the number of bottles filled,

Let T be the time in hours.

Given that the number of bottles filled is proportional to the amount of time the machine runs, we have

\begin{gathered} N\propto T \\ \text{Introducing a proportionality constant, we have } \\ N\text{ = kT} \\ \Rightarrow k\text{ = }\frac{N}{T} \\  \end{gathered}

Let's evaluate the value of k for each day.

Thus, on monday,

\begin{gathered} N\text{ = 9900} \\ T\text{ = 5.5} \\ \text{thus,} \\ k\text{ = }\frac{9900}{5.5} \\ \Rightarrow k\text{ = 1800} \end{gathered}

Tuesday:

\begin{gathered} N\text{ = }11160 \\ T\text{ = }6.2 \\ \text{thus,} \\ k\text{ = }\frac{11160}{6.2} \\ \Rightarrow k\text{ = 1800} \end{gathered}

Wednesday:

\begin{gathered} N\text{ = }12330 \\ T\text{ = }6.25 \\ \text{thus,} \\ k\text{ = }\frac{12330}{6.25} \\ \Rightarrow k\text{ = 1972.8} \end{gathered}

Thursday:

\begin{gathered} N\text{ = }10440 \\ T\text{ = }5.80 \\ \text{thus,} \\ k\text{ = }\frac{10440}{5.8} \\ \Rightarrow k=1800 \end{gathered}

It is observed that all exept wednesday have the same value of k.

Thus, the amount of time required for the number of bottles filled on wednesday is evaluated as

\begin{gathered} N\text{ = }12330 \\ k\text{ = 1800} \\ T\text{ = ?} \\ \text{but} \\ k\text{ = }\frac{N}{T} \\ 1800\text{ = }\frac{12330}{T} \\ \Rightarrow T\text{ = }\frac{\text{12330}}{1800} \\ T\text{ = 6.85} \end{gathered}

Hence, the incorrect day is Wednesday. The amount of time for that many bottles should be 6.85 hours.

3 0
1 year ago
GUYS PLEASE HELP IM IN NEED I WILL MARK BRAINLIEST
jekas [21]
The answer would be 1/3 up 1 over 3.
6 0
3 years ago
Read 2 more answers
L^2+7L-30<br><br> I need the answer for hw
Romashka [77]

Answer:

(l-3)(l+10)

Step-by-step explanation:

7 0
1 year ago
Write a function in the form y=mx+b for the line that contains the points (-6.4, -2.6) and (5.2, 9)
allsm [11]
First solve for the slope, m using the two points given. It doesn't matter which point you choose as point 1 or 2 as long as you're consistent.

m = (y2 - y1)/(x2 - x1)

point 1: (–6.4, –2.6)

point 2: (5.2, 9)

m = (9 - -2.6)/(5.2 - -6.4)
m = (9 + 2.6)/(5.2 + 6.4)
m = 11.6/11.6
m = 1

put the newly found slope into the linear equation for m

y = (1)x + b
y = x + b

Now solve for the y-intercept, b
by putting one of the given points

9 = 5.2 + b

b = 9 - 5.2
b = 3.8

final equation:

y = x + 3.8
7 0
3 years ago
How many mL of medication are needed to last 10 days if the dose of medication is 2.5 tsp TID (three times a day)?
rjkz [21]

Answer:

369.7 mL of medication

Step-by-step explanation:

How many mL of medication are needed to last 10 days if the dose of medication is 2.5 tsp TID (three times a day)?

From the above question,

The dosage of the medication =

2.5 tsp 3 times a day

= 2.5 × 3 = 7.5 tsp per day.

Since

1 day = 7.5 tsp

10 days = x tsp

Cross Multiply

x = 10 × 7.5 tsp

x = 75 tsp of medication for 10 days.

Step 2

It is important to note that:

1 tsp = 4.929 mL

75 tsp = x mL

Cross Multiply

x = 75 × 4.929 mL

x = 369.669 mL of medication

Approximately = 369.7 mL of medication

7 0
2 years ago
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