8x - 4y = -12 solve for y

1 answer:

4 0

Solving an equation means finding a value of a variable that make the equation true. This value is called the solution of the equation. A mathematical equation is just like a balanced equation. Both sides of the equation should be equal at all times. Whatever we do to one side, has to be done on the opposite side.

$8x - 4y = -12$

$4(2x-y)=-12

 
$ $Factor \ out \ the \ common \ term \ 4$

$2x-y=- \dfrac{12}{4}$ $Divide \ both \ sides \ by \ 4$

$2x-y=-3

 

$

$-y=-3-2x$ $Subtract \ 2x \ from \ both \ sides$

$y=3+2x$ $Multiply \ both \ sides \ by \ -1$

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Artist 52 [7]

Answer:

Read explain

Step-by-step explanation:

The steps taken to solve this system of equations would first be:

1. Sub 4x-2 into your first equation, 2x+5(4x-2)= 12 ->

2. Solve/simplify this equation to get x=1

3. Sub x=1 into your second equation and solve for y = 2

4. Get the solution (1,2)

7 0

2 years ago

Find all solutions of the equation: 2cos^2x-cosx=1

Art [367]

If you're using the app, try seeing this answer through your browser: brainly.com/question/3166243

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Solve the trigonometric equation:

$\mathsf{2\,cos^2\,x-cos\,x=1}\\\\ \mathsf{2\,cos^2\,x-cos\,x-1=0}$

Make a substitution:

$\mathsf{cos\,x=t\qquad (-1\le t\le 1)}$

and the equation becomes

$\mathsf{2t^2-t-1=0}$

Rewrite conveniently – t as + t – 2t, and then factor the left-hand side by grouping:

$\mathsf{2t^2+t-2t-1=0}\\\\ \mathsf{t\cdot (2t+1)-1\cdot (2t+1)=0}$

Factor out 2t + 1:

$\mathsf{(2t+1)\cdot (t-1)=0}\\\\ \begin{array}{rcl} \mathsf{2t+1=0}&~\textsf{ or }~&\mathsf{t-1=0}\\\\ \mathsf{2t=1}&~\textsf{ or }~&\mathsf{t=1}\\\\ \mathsf{t=\dfrac{\,1\,}{2}}&~\textsf{ or }~&\mathsf{t=1} \end{array}$

Substitute back for t = cos x:

$\begin{array}{rcl}\mathsf{cos\,x=\dfrac{\,1\,}{2}}&~\textsf{ or }~&\mathsf{cos\,x=1}\\\\ \mathsf{cos\,x=cos\,60^\circ}&~\textsf{ or }~&\mathsf{cos\,x=cos\,0} \end{array}$

Therefore,

$\begin{array}{rcl} \mathsf{x=\pm\,60^\circ+k\cdot 360^\circ}&~\textsf{ or }~&\mathsf{cos\,x=0+k\cdot 360^\circ} \end{array}$

where k is an integer.

Solution set:

$\mathsf{S=\left\{x\in\mathbb{R}:~~x=-\,60^\circ+k\cdot 360^\circ~~or~~x=60^\circ+k\cdot 360^\circ~~or~~x=k\cdot 360^\circ,~~k\in\mathbb{Z}\right\}}$

I hope this helps. =)

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2 years ago

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Setler [38]

B pretty sure that it’s that

8 0

3 years ago

Read 2 more answers

Justify each step in solving the equation 5(y+3)-11=-y-6 by writing a reason for each statement.

liubo4ka [24]

Explanation:

5(y+3)-11=-y-6 Given