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frosja888 [35]
3 years ago
12

Which items are discounted less than 15%? Select all that apply.

Mathematics
1 answer:
Annette [7]3 years ago
3 0
Put each starting price of the item into google (ex. "15% off of 199.99). If the number is higher than the after price it is higher than 15% off, but if it lower than the after price then it is discounted lower than 15%.
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Dora is building the right square pyramid shown in the diagram.
saul85 [17]
Answer is 4 :) I hope it help you.
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Ln x-ln(x-5)=ln2<br> Help in this problem please having problems on my homework
Eddi Din [679]
17 because you need to multiply
3 0
3 years ago
What is the volume of the sphere that has a diameter of 3? use 3.14 for pie​
aev [14]

Hey ! there

Answer:

  • <u>1</u><u>1</u><u>3</u><u>.</u><u>0</u><u>4</u><u> </u><u>unit </u><u>cube</u>

Step-by-step explanation:

In this question we are provided with a sphere <u>having</u><u> </u><u>radius </u><u>3 </u><u>units </u>and <u>value </u><u>of </u><u>π </u><u>is </u><u>3.</u><u>1</u><u>4</u><u> </u><u>.</u><u> </u>And we're asked to find the<u> </u><u>volume</u><u> of</u><u> </u><u>sphere</u><u> </u><u>.</u>

For finding volume of sphere , we need to know its formula . So ,

\qquad \qquad \: \underline{\boxed{ \frak{Volume_{(Sphere)} =  \dfrac{4}{3} \pi r {}^{3} }}}

<u>Where</u><u> </u><u>,</u>

  • π refers to <u>3.</u><u>1</u><u>4</u>

  • r refers to <u>radius</u><u> of</u><u> sphere</u>

<u>Sol</u><u>u</u><u>tion </u><u>:</u><u> </u><u>-</u>

Now , we are substituting value of π and radius in the formula ,

\quad \longrightarrow \qquad \: \dfrac{4}{3}   \times 3.14 \times (3) {}^{3}

Simplifying it ,

\quad \longrightarrow \qquad \: \dfrac{4}{3}  \times 3.14 \times 3 \times 3 \times 3

Cancelling 3 with 3 :

\quad \longrightarrow \qquad \: \dfrac{4}{ \cancel{3}}  \times 3.14 \times 3 \times 3 \times  \cancel{3}

We get ,

\quad \longrightarrow \qquad \:4 \times 3.14 \times 9

Multiplying 4 and 3.14 :

\quad \longrightarrow \qquad \:12.56 \times 9

Multiplying 12.56 and 9 :

\quad \longrightarrow \qquad \:    \pink{\underline{\boxed{\frak{113.04  \: unit \: cube}}}} \quad \bigstar

  • <u>Henceforth</u><u> </u><u>,</u><u> </u><u>volume</u><u> </u><u>of</u><u> </u><u>sphere</u><u> </u><u>having </u><u>radius </u><u>3 </u><u>units </u><u>is </u><em><u>1</u></em><em><u>1</u></em><em><u>3</u></em><em><u> </u></em><em><u>.</u></em><em><u>0</u></em><em><u>4</u></em><em><u> </u></em><em><u>units </u></em><em><u>cube </u></em><em><u>.</u></em>

<h2><u>#</u><u>K</u><u>e</u><u>e</u><u>p</u><u> </u><u>Learning</u></h2>

5 0
2 years ago
Solve 2x-3&lt; 2<br>please answer it fast ​
murzikaleks [220]

Answer:

x<5/2

Step-by-step explanation:

We have

2x−3<2

Add 3 to both sides.

2x−3 +3 <2 +3

which makes

2x<5

Divide both sides by 2.

2x/2 < 5/2

x<5/2

4 0
2 years ago
5-6(a+2)=7+a<br> What is a
iogann1982 [59]
Remmeber you can do anything to an equaiton as long as you do it to btoh sides
5-6(a+2)=7+a
distribute
5-6a-12=7+a
add like terms
-6a-7=7+a
add 6a both sides
-7=7+7a
minus 7 both sides
-14=7a
divide by 7
-2=a
a=-2
5 0
3 years ago
Read 2 more answers
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