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evablogger [386]
3 years ago
13

A die is rolled 8 times. given that there were 3 sixes in the 8 rolls, what is the probability that there were 2 sixes in the fi

rst five rolls
Mathematics
1 answer:
Eva8 [605]3 years ago
8 0
Answer: 15/28
Suppose the following:
event A: the event that there were 3 sixes in the 8 roles,
event B: the event that there were 2 sixes in the first 5 roles.
Then the conditional probability to find is P(B|A)=P(A∩B)/P(A).
P(A)=C(3,8)*(1/6)^3*(5/6)^5,
P(A∩B)=C(2,5)*(1/6)^2*(5/6)^3*C(1,3)*(1/6)*(1/6)^2
∴P(B|A)=15/28
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Waves with an amplitude of 2 feet pass a dock every 30 seconds. Write an equation for a cosine function to model the height of a
kolbaska11 [484]

Answer:

The cosine function to model the height of a water particle above and below the mean water line is h = 2·cos((π/30)·t)

Step-by-step explanation:

The cosine function equation is given as follows h = d + a·cos(b(x - c))

Where:

\left | a \right | = Amplitude

2·π/b = The period

c = The phase shift

d = The vertical shift

h = Height of the function

x = The time duration of motion of the wave, t

The given data are;

The amplitude \left | a \right | = 2 feet

Time for the wave to pass the dock

The number of times the wave passes a point in each cycle = 2 times

Therefore;

The time for each complete cycle = 2 × 30 seconds  = 60 seconds

The time for each complete cycle = Period = 2·π/b = 60

b = π/30 =

Taking the phase shift as zero, (moving wave) and the vertical shift as zero (movement about the mean water line), we have

h = 0 + 2·cos(π/30(t - 0)) = 2·cos((π/30)·t)

The cosine function is h = 2·cos((π/30)·t).

4 0
3 years ago
How do you write 100, in an exponential form
Allushta [10]

1. 10^2

2. 10^5

3. 10^4

Hope this helped!

Nate

8 0
3 years ago
Pizza planet is running a speacial.3 pizzas for 16.50 what is the unit rate for one pizza
drek231 [11]
For this you divide the total spent by the total number of pizzas...
16.50/ 3 = $5.50 per pizza.
6 0
3 years ago
Pschological tests are often used to determine the hostility levels in people. High scores on the HLT pschological test correspo
algol13

Answer:  the correct answer is we are 95% confident that there is no statistically significant difference in the mean treatment  methods for hostility.  

Step-by-step explanation:

1)  Test for the equality of variances in the two groups to choose the appropriate t-test.  

H0: σ (1)^2 = σ (2)^2  

Ha: σ (1)^2 ≠ σ (2)^2  

Larger variance = 64  

Smaller variance = 49  

F = 1.30612  

Degrees of freedom 15 and 9  

Critical F from the table (with alpha=0.05) = 2.58  

Calculated F is smaller than critical F, so we use the pooled variance t-test.  

Sample 1 size 7  

Sample 2 size 8  

Sample 1 mean 79  

Sample 2 mean 84  

Sample 1 S.D. 7  

Sample 2 S.D. 8  

Pooled S.D = [(n1-1)s1^2+(n2-1)s2^2]/(n1+n2-2)

Pooled variance s = [(6)(49)+(7)(64))] / (13) =  (294+448)/13=742/13=57.076923

Pooled variance s^2 = 57.076923  

Standard error of difference in means = sqrt(1/n1+1/n2) times sqrt(s^2)  

Standard error of difference in means = (0.517549)(7.554927) = 3.910046 (denominator of t)  

Confidence interval = (mean1-mean2) +/- t SE  

t is the critical t with 24 degrees of freedom = 2.056  

(79 - 84) +/- (2.056) (3.910046)  

= (-13.04, 3.04)  

Interval encloses 0  

We are 95% confident that there is no statistically significant difference in the mean treatment  methods for hostility.  

4 0
3 years ago
16-z=12 solve equation​
sammy [17]

z=4

16-4=12

esta es la respuesta

7 0
3 years ago
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