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Monica [59]
3 years ago
15

This loop is a good choice when you know how many times you want the loop to iterate in advance of entering the loop.1. do-while

2. while3. for4. infinite5. None of these
Computers and Technology
1 answer:
Luba_88 [7]3 years ago
6 0

Answer:

Option 3 is the correct answer.

Explanation:

  • In c, c++ or Java programming language, The for loop takes three parameters in which first is an initialization, second is condition check and the third is an increment. None of the other loop (except for loop) takes three parameters. The other loop takes only one parameter and that is the condition check.
  • So when a user knows about the times of iteration then it is a good choice to use the for loop but when the person does not know about the times of iteration if the loop. It means the iteration of the loop is based on the condition then it is a good choice to chose while or Do-while loop.
  • The above question wants to ask which loop for a user can best if he familiar with the iteration of the loop then the answer is for loop which is started from option 3. Hence Option 3 is the correct answer while the other is not because--
  1. Option 1 states about the do-while loop which takes condition only.
  2. Option 2 states about the while loop which also takes condition only.
  3. Option 4 states about the infinite loop which is not any loop.
  4. Option 5 states about none of these which is not correct because option 3 is the correct answer.

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Lady_Fox [76]

Answer:

Line 2: for numF in [3, 5]

Line 1: for numE in [2, 6]

Line 3: print(numE, numF)

Explanation:

From the outputs, the first number of the first output is 2. This means that <em>numE in [</em><em>2</em><em>, 6]</em> would be on the first line.

The second number of the first output is 3, concluding that <em>numF in [</em><em>3</em><em>, 5]</em> is within a nested loop, meaning it would be on the second line.

This leaves <em>print(numE, numF)</em> on line 3.

We can go through the lines step by step to check if we have placed them in the correct order:

Code

for numE in [2, 6]:

 for numF in [3, 5]:

   print(numE, numF)

During the first iteration, numE = 2 and numF = 3.

Output: 2, 3

Since [3, 5] is in a nested loop, we need to finish iterating all of its numbers before numE moves to the next number, so:

numF moves to 5, numE stays at 2.

Output: 2, 5

Since we have finished iterating through [3, 5], numE moves to 6 and numF starts back at 3:

Output: 6, 3

numE still stays at 6 and numF iterates to 5 since [3, 5] is in a nested loop:

Output: 6, 5

The outputs match the outputs on the sheet, meaning we have correctly placed the code in order.

Hope this helps :)

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The answer to your question is,

C. Address Block

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All it services and servers are equally critical. <br> a. True <br> b. False
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False

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Answer:

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7 0
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Olegator [25]

<u>Answer:</u>

<em>There are 2 ways to do extract the decimal part: </em>

<u>Explanation:</u>

  • <em>First method using number  </em>

<em>int main() { </em>

<em>  double num = 23.345; </em>

<em>  int intpart = (int)num; </em>

<em>  double decpart = num - intpart; </em>

<em>  printf(""Num = %f, intpart = %d, decpart = %f\n"", num, intpart, decpart); </em>

<em>} </em>

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<em>#include <stdlib.h> </em>

<em>int main() </em>

<em>{ </em>

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<em>    long mantissa = strtod(loc+1, endptr); </em>

<em>    long whole = strtod(inStr, endptr);  </em>

<em>    printf(""whole: %d \n"", whole);      </em>

<em>    printf(""mantissa: %d"", mantissa);   </em>

<em>} </em>

8 0
3 years ago
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