Answer:
void print_popcorn_time(int bag_ounces){
if(bag_ounces < 3){
cout<<"Too small"<<endl;
}else if(bag_ounces > 10){
cout<<"Too large"<<endl;
}else{
cout<<(6 * bag_ounces)<<"seconds"<<endl;
}
}
Explanation:
The function is the block of the statement which performs the special task.
For checking the condition in the program, the if-else statement is used.
It can check the condition one or two but if we want to check the more than two different conditions then the continuous if-else statement is used.
syntax of continuous if else:
if(condition){
statement;
}else if(condition)
statement;
}else{
statement;
}
In the question, there are three conditions;
1. bag_ounces is less than 3
2. bag_ounces greater than 10
3. else part.
we put the condition in the above if-else statement and print the corresponding message.
Your Decision but a good one will be exploring the ocean or the underground it will be very shocking if you find something no one ever has found.
In our bag, 1/2 is peanuts, 1/4 is chocolate and 1/4 is dried fruit.
The likelihood of drawing a chocolate therefore is 1/4.
The likelihood of drawing a peanut is 1/2 and the likelihood of drawing a dried fruit is 1/4.
Thus, D is the correct answer because the 1/4 likelihood of drawing a chocolate is less than the 1/2 chance of drawing a peanut.
