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djverab [1.8K]
4 years ago
11

Jessica is at a charity fundraiser and has a chance of receiving a gift. The odds in favor of receiving a gift are 5/12. Find th

e probability of Jessica receiving a gift.
Mathematics
1 answer:
Goryan [66]4 years ago
3 0

Answer:

5/17

Step-by-step explanation:

This is a question to calculate probability from odds. The formula is given as:

A formula for calculating probability from odds is P = Odds / (Odds + 1)

From the question , we are told that the odds of receiving a gift is

= 5:12

The probability of Jessica receiving a gift =

Probability = Odds / (Odds + 1)

P = 5/12 / ( 5/12 + 1)

P = (5/12)/ (17/12)

P = 5/12 × 12/17

= 5/17

Therefore, the probability of Jessica. receiving a gift is 5/17.

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Answer:

3 years

Step-by-step explanation:

A=P( 1+rt)

A= Total amount

P= Principal

r = yearly interest

t= time in year

672=600(1+0.04t). Distribute

672=600+600x0.04t

72= 24t

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Read 2 more answers
An industry representative claims that 10 percent of all satellite dish owners subscribe to at least one premium movie channel.
Greeley [361]

Answer: 1) 0.6561    2) 0.0037

Step-by-step explanation:

We use Binomial distribution here , where the probability of getting x success in n trials is given by :-

P(X=x)=^nC_xp^x(1-p)^{n-x}

, where p =Probability of getting success in each trial.

As per given , we have

The probability that any satellite dish owners subscribe to at least one premium movie channel.  : p=0.10

Sample size : n= 4

Let x denotes the number of dish owners in the sample subscribes to at least one premium movie channel.

1) The probability that none of the dish owners in the sample subscribes to at least one premium movie channel = P(X=0)=^4C_0(0.10)^0(1-0.10)^{4}

=(1)(0.90)^4=0.6561

∴ The probability that none of the dish owners in the sample subscribes to at least one premium movie channel is 0.6561.

2) The probability that more than two dish owners in the sample subscribe to at least one premium movie channel.

= P(X>2)=1-P(X\leq2)\\\\=1-[P(X=0)+P(X=1)+P(X=2)]\\\\= 1-[0.6561+^4C_1(0.10)^1(0.90)^{3}+^4C_2(0.10)^2(0.90)^{2}]\\\\=1-[0.6561+(4)(0.0729)+\dfrac{4!}{2!2!}(0.0081)]\\\\=1-[0.6561+0.2916+0.0486]\\\\=1-0.9963=0.0037

∴ The probability that more than two dish owners in the sample subscribe to at least one premium movie channel is 0.0037.

8 0
3 years ago
ILL GIVE BRAINLIEST PLS HELP
yan [13]

Answer:

1/5

Step-by-step explanation:

The stick has a length of 5 units

The stick is broken at two points chosen at random

First break: the probability that you get a piece that is 1 unit or longer than 1 units= 1/5.

Second break, the probability that you get a piece that is 1 unit or longer than 1 units is 1/5.

Therefore,

The total probability =probability of first break * probability of second break * original stick unit

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Step-by-step explanation:

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