The answer is -69.67
22.5 + x = -47.47
-22.5 -22.5
x = -69.87
Answer:
See below.
Step-by-step explanation:
Shape A is congruent to shape <u>___F___</u>, as shown by a reflection across the y-axis and then a translation down <u>__3___</u> units. B is congruent to shape <u>__D__</u>, as shown by a reflection across the y-axis and then a translation down <u>__2___</u> units
Answer:
145
Step-by-step explanation:
Its the opposite angle of 145
Step-by-step explanation:
The system of linear equations are , (i) y = 2x and (ii) y = x + 1 . We will find some coordinates and then we will plot its graph. The point where both Graphs will meet will be the solution of the graph .
<u>•</u><u> </u><u>Findin</u><u>g</u><u> </u><u>coordinates</u><u> </u><u>of </u><u>Equ</u><u>ⁿ</u><u> </u><u>(</u><u>i</u><u>)</u><u> </u><u>:</u><u>-</u>
Step 1 : <u>Put</u><u> </u><u>x</u><u> </u><u>=</u><u> </u><u>0</u><u> </u><u>:</u><u>-</u>

Step 2: <u>Put</u><u> </u><u>x</u><u> </u><u>=</u><u> </u><u>1</u><u> </u><u>:</u><u>-</u><u> </u>


<u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u>
<u>•</u><u> </u><u>Finding</u><u> </u><u>coord</u><u>inates</u><u> </u><u>of</u><u> </u><u>equⁿ</u><u> </u><u>(</u><u>ii</u><u>)</u><u> </u><u>:</u><u>-</u>
Step 1 : Put x = 0 :-

Step 2: Put x = 1 :-


Now plot these points on the graph Taking appropriate scale . Refer to the attachment in graph . From graph the Solution is (1,2) .