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Triss [41]
3 years ago
15

I need help with 5 and 6

Mathematics
1 answer:
8_murik_8 [283]3 years ago
7 0

Answer:

w = 6

RS = 13

Step-by-step explanation:

RS + ST = RT

(2w + 1) + (w - 1) = 18

3w = 18

; w = 6

Hence the value of RS = 2(6) + 1

; RS = 13

AC = AB + BC

56 = (x + 16) + (5x + 10)

56 = 6x + 26....then rearrange the equation to form...;

56 - 26 = 6x

30 = 6x...

where...; x = 5

AB = 5 + 16 and BC = 5(5) + 10

;AB = 21 ;BC = 35

You might be interested in
20 points pls help no links
aniked [119]

Answer:

(-15, 13)

Step-by-step explanation:

-3(8x + 9y = -3)

4( 6x + 7y = 1)

-24x - 27y = 9

24x + 28y = 4 (add both equations)

y = 13

6x + 7*13= 1

6x + 91= 1

6x = 1 -91

x = -91/6

x = -15

3 0
3 years ago
Julian saved between $ 30 and $ 52 over the summer. His friend Daniela saved twice as much. Let n represent the amount of money
maks197457 [2]

Y = (30 + 52) * 2

Y = (82) * 2

Y = 164

Daniela saved $164

3 0
3 years ago
What is 4 1/2 pint to quart?
Ivanshal [37]

There are two pints every quarter.

So let's convert pints to quarter

   \frac{4\frac{1}{2} }{2} =\frac{\frac{9}{2} }{2} = \frac{9}{4}

There 4 1/2 pint is to 9/4 quarter.

Hope that helps!

p.s. look at my diagram to help you remember

5 0
2 years ago
What are the powers of 4 through 1000
Ahat [919]

Answer:

{4^0, 4^1, 4^2, 4^3, 4^4}, or, with a bit of rounding off,

{4^0, 4^1, 4^2, 4^3, 4^4, 4^5} = {1, 4, 16, 64, 256, 1024}

Step-by-step explanation:

I wanted to determine the largest power of 4 that does not exceed 1000.  Here's what I did:  

4^x = 1000.  Taking the ln of both sides, we get x ln 4 = ln 1000.

                               6.9078

Solving for x:  x = --------------- = 4.98

                                1.3863

Thus, the answer to this question is {4^0, 4^1, 4^2, 4^3, 4^4}.  If you're willing to talk in terms of approximations, then there'd be one more power of 4 in this set:  4^5.  Note that 4^5 = 1024, whidh is just a bit over 1000.

7 0
3 years ago
98 Points!<br><br> (3x^2^a - 4y^a z^3a )^2
vfiekz [6]

((3x^2)^a - (4y^a)(z^3a))^2

First, expand.

((3x^2)^a - (4y^a)(z^3a)) ((3x^2)^a - (4y^a)(z^3a))

Combine

3^(2a) - x^(4a) - 8 * 3^(2a)x^(2a)y^(a)z^(3a) + 16y^(3a)z^(6a)

hope this helps

5 0
3 years ago
Read 2 more answers
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