Answer:
<u>630</u> MP3 players are likely to be defective.
Step-by-step explanation:
Given:
A shipment to a warehouse consists of 4500 MP3 players the manager chooses a random sample of 50 MP3 players and finds that 7 are defective.
Now, to find the MP3 players which are likely to be defective.
Let the defective MP3 players be ![x.](https://tex.z-dn.net/?f=x.)
Total MP3 players = 4500.
In sample of 50 MP3 players 7 are defective.
Now, setting the proportion:
If, 50 is equivalent to 7.
Then, 4500 is equivalent to ![x.](https://tex.z-dn.net/?f=x.)
Now, to solve using cross multiplication method:
![\frac{50}{7} =\frac{4500}{x}](https://tex.z-dn.net/?f=%5Cfrac%7B50%7D%7B7%7D%20%3D%5Cfrac%7B4500%7D%7Bx%7D)
<em>By cross multiplying we get:</em>
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<em>Dividing both sides by 50 we get:</em>
![x=630.](https://tex.z-dn.net/?f=x%3D630.)
Therefore, 630 MP3 players are likely to be defective.