Question

Can someone help me plz .. Use these lengths to find cos B, tan B, and sin B.

Answer 1

Answer:

cos B = $\frac{7}{25}$

tan B = $\frac{24}{7}$

sin B = $\frac{24}{25}$

Step-by-step explanation:

In the right triangle, there are three sides and 2 acute angles

• Hypotenuse ⇒ the opposite side of the right angle

• Leg1 and Leg 2 ⇒ the sides of the right angle

The trigonometry functions of one of the acute angles Ф are

• sin Ф = opposite leg/hypotenuse

• cos Ф = adjacent leg/hypotenuse

• tan Ф = opposite leg/adjacent leg

In Δ ACB

∵ ∠C is the right angle

∴ AB is the hypotenuse

∵ AC is the opposite side of ∠B ⇒ leg1

∵ CB is the adjacent side of ∠B ⇒ leg2

→ By using the ratios above

∴ cos B = $\frac{CB}{AB}$ , tan B = $\frac{AC}{CB}$ , sin B = $\frac{AC}{AB}$

∵ CB = 7, AB = 25, AC = 24

∴ cos B = $\frac{7}{25}$

∴ tan B = $\frac{24}{7}$

∴ sin B = $\frac{24}{25}$