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Ivahew [28]
3 years ago
10

I need help with 12, 13, 14, and 15

Mathematics
1 answer:
frutty [35]3 years ago
6 0
Number 12 what do you think we do first
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6. Find the surface area of the triangular prism.<br> 3<br> 4.<br> 4<br> 5
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Answer:

the answer is 345 4 like it literally says it on the paper like how could you not know that like it's on the

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3 years ago
Jada is three years older than twice her brothers age. Select all equations that correctly represent the relationship between Ja
goblinko [34]

Answer:

1,2, and 5

Step-by-step explanation:

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The first hole of a golf course is 250 metres long. A golfer hits her drive exactly 250 m,
Serga [27]

Answer: A golfer finds himself in two different situations on different holes. On the second hole he is 120 m from the green and wants to hit the ball 90 m

Step-by-step explanation:

7 0
1 year ago
Carbon-14 is a radioactive isotope that has a half-life of 5,730 years. Approximately how many years will it take for carbon-14
PilotLPTM [1.2K]

Answer:

<em>Carbon-14 will take 19,035 years to decay to 10 percent.</em>

Step-by-step explanation:

<u>Exponential Decay Function</u>

A radioactive half-life refers to the amount of time it takes for half of the original isotope to decay.

An exponential decay can be described by the following formula:

N(t)=N_{0}e^{-\lambda t}

Where:

No  = The quantity of the substance that will decay.

N(t) = The quantity that still remains and has not yet decayed after a time t

\lambda     = The decay constant.

One important parameter related to radioactive decay is the half-life:

\displaystyle t_{1/2}=\frac {\ln(2)}{\lambda }

If we know the value of the half-life, we can calculate the decay constant:

\displaystyle \lambda=\frac {\ln(2)}{ t_{1/2}}

Carbon-14 has a half-life of 5,730 years, thus:

\displaystyle \lambda=\frac {\ln(2)}{ 5,730}

\lambda=0.00012097

The equation of the remaining quantity of Carbon-14 is:

N(t)=N_{0}e^{-0.00012097\cdot t}

We need to calculate the time required for the original amout to reach 10%, thus N(t)=0.10No

0.10N_o=N_{0}e^{-0.00012097\cdot t}

Simplifying:

0.10=e^{-0.00012097\cdot t}

Taking logarithms:

ln 0.10=-0.00012097\cdot t

Solving for t:

\displaystyle t=\frac{log 0.10}{-0.00012097}

t\approx 19,035\ years

Carbon-14 will take 19,035 years to decay to 10 percent.

6 0
3 years ago
Read 2 more answers
Find the solution set. |x|= 9<br> A. { }<br> B. {-3 , 3}<br> C. { -9, 9}<br> D. {-81, 81}
Ierofanga [76]

Answer:

C. { -9, 9}

Step-by-step explanation:

An absolute value equation has 2 solutions, a positive and a negative

|x|= 9

x= +9  and x = -9

4 0
3 years ago
Read 2 more answers
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