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VikaD [51]
3 years ago
13

2.In quadratic equation ax2 + bx + c = 0, if discriminant is D= b2 - 4ac, then roots of the quadratic equation are

Mathematics
1 answer:
tino4ka555 [31]3 years ago
3 0

Answer:

(2) Real and equal (i.e., repeated roots), if D = 0.

Step-by-step explanation:

.In a quadratic equation ax2 + bx + c = 0, if discriminant is D= b2 - 4ac, then roots of the quadratic equation are

Real and equal (i.e., repeated roots), if D = 0.

If the D > b² - 4ac then it's real and distinct.

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Find the quotient. (3. 683 × 104) (7. 51 × 1012) What is the solution in scientific notation? 4. 9041 × (-9)10 4. 9041 × 10-9 4.
ollegr [7]

The value of the expressions (3.683 × 10⁴) and (7.51 × 10¹²) in scientific notation is 4.9041 × 10⁻⁹. Then the correct option is B.

<h3>What is division?</h3>

The division means the separation of something into different parts, sharing of something among different people, places, etc.

The expressions are (3.683 × 10⁴) and (7.51 × 10¹²).

We have to divide (3.683 × 10⁴) from (7.51 × 10¹²).

\dfrac{3.683 * 10^4}{7.51*10^{12}}\\\\0.4904*10^{-8}\\\\4.9041*10^{-9}

More about the division link is given below.

brainly.com/question/369266

6 0
2 years ago
Find the output, y, when the input, x, is 3.<br><br> Y=-5x+13
Alexeev081 [22]

Answer:

y = -2

Step-by-step explanation:

y = -5x + 13

x = 3

y = -5(3) + 13

y = -15 + 13

y = -2

4 0
2 years ago
Read 2 more answers
Please help. 20 points and brainliest.
julia-pushkina [17]

Answer:

minimum -45, maximum 32

Step-by-step explanation:

C=4x-3y

x≥0, y≥4, x+y≤15

Maximum value of C can be achieved at max x and min y

  • min y=4 => max x=15-4=11
  • C=4*11-3*4= 32

Minimum value of C can be achieved at min x and max y

  • min x=0, max y =15
  • C=4*0-3*15= -45

So answer is minimum -45, maximum 32

7 0
3 years ago
Jesse looks out the attic window of his home, which is 22 ft above the ground. At an angle of elevation of 35° he sees a bird si
Ket [755]

Answer:

Step-by-step explanation:

6 0
3 years ago
What is the fourth term of the binomial expansion for (3x-2y)6
Thepotemich [5.8K]
One way is to just expand it by using binomial theorem
or to use pascal's triangle

ok so

to find the nth term of a binomial, (a-b). where the binomial is to the r power you do
n-1=k

rCk times (a)^{r-k}(-b)^k
and rCk=\frac{r!}{k!(r-k)!}

so

4th term
4-1=3
6 is exponent

6C3(3x)^{6-3}(-2y)^3=
( \frac{6!}{3!(6-3)!} )((3x)^3(-8y^3)=
( \frac{6*5*4}{1*2*3} )(27x^3)(-8y^3)=
(20)(27)(-8)(x^3)(y^3)=-4320x^3y^3



the 4th term is -4320x^3y^3

7 0
3 years ago
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