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fiasKO [112]
3 years ago
15

How many ways can five cards be selected from a standard deck of 52 cards?​

Mathematics
1 answer:
elena55 [62]3 years ago
6 0

Step-by-step explanation:

If the order of the cards doesn't matter:

₅₂C₅ = 52! / (5! (52−5)!)

₅₂C₅ = 2,598,960

If the order of the cards does matter:

52 × 51 × 50 × 49 × 48 = 311,875,200

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Find the best buy (based on price per unit) for cereal.
Salsk061 [2.6K]
Answer:

21-ounce size: $3.89

Explanation:

To compare the cost, you can calculate the cost per ounce of cereal. This means you will have to divide the cost by the total number of ounces. The cereal that costs the least per ounce will be the best buy.

$4.79 / 18oz = $0.27/oz

$3.89 / 21oz = $0.19/oz

$6.49 / 32oz = $0.20/oz

The 21-ounce size is has the cheapest price per ounce, so this is your best buy.
3 0
4 years ago
Rewrite the expression using the properties of exponents. <br><br> x5<br> y4
DanielleElmas [232]
5x 4x hope this helped u
3 0
3 years ago
A contractor purchases a shipment of 100 transistors. It is his policy to test 10 of these transistors and to keep the shipment
Serjik [45]

Answer:

Hence the probability of the at least 9 of 10 in working condition is 0.3630492

Step-by-step explanation:

Given:

total transistors=100

defective=20

To Find:

P(X≥9)=P(X=9)+P(X=10)

Solution:

There  are 20 defective and 80 working transistors.

Probability of at least 9 of 10 should be working out 80 working transistors

is given by,

P(X≥9)=P(X=9)+P(X=10)

<em>{80C9 gives set of working transistor and 20C1 gives 20 defective transistor and 100C10 is combination of shipment of 10 transistors}</em>

P(X≥9)={80C9*20C(10-9)}/(100C10)+{80C10*20(10-10)}/(100C10)

<em>(Use the permutation and combination calculator)</em>

P(X≥9)=(231900297200*20/17310309456440)

+(1646492110120/17310309456440)

P(X≥9)=0.267933+0.0951162

P(X≥9)=0.3630492

4 0
3 years ago
HELP!!!!!!!!!!!!!
Misha Larkins [42]

Answer:

P'(7,0)Q'(2,1) R'(12,-6)

Step-by-step explanation:

P(3,5)------>P'(3+4,5-5)

P'(7,0)

Q(-2,6)----->Q'(-2+4,6-5)

Q'(2,1)

R(8,-1)------>R'(8+4,-1-5)

R'(12,-6)

8 0
4 years ago
Solve 15 ≥ -3x or 2/3 x ≥ -2.
hjlf
Solve each of the equations independently, then determine if the are continuous or discontinuous. 
15≥-3x [start here]
-5≤x    [divide both sides by (-3). *Dividing by a negative number means the direction of the sign changes!]
x≥-5  [just turned around for analysis]

Next equation:
2/3x≥-2    [start here]
x≥-2(3/2)  [multiply both sides of the equation by the reciprocal, 3/2)
x≥-3

So, (according to the first equation) all values of x must be greater than, or equal to -5.

(According to the second equation) all values of x must be greater than, or equal to -3. 
So, when graphed on a number line, both equations graph in the same direction, so they are continuous.

4 0
3 years ago
Read 2 more answers
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