Well in a right angle triangle, we know that angle C would be 90 degrees, we can check this by solving for X and seeing if the expression 2x will give us a value of 90 degrees.
So 2x = 90
X = 90/2
X = 45 degrees.
90 = 2x
90 = 2(45)
90 = 90.
Thus since the equation is true, X = 45 degrees, we can also solve for the remaining angles knowing what X is.
There you go. Let me know if you have questions
the formula is a_{1}+(n-1) d
so a_{1} would be the first number in the sequence, which would be 13 in problem 9.
13+(n-1)d
then you put in n, which is 10 (it represents which number in the sequence you're looking for, for example 16 is the second number in the sequence)
13+(10-1)d
then you find the difference between each number, represented by d which in this case is 3
13+(10-1)3
13+(9)3
13+27=
40
The walkway is 1.5 m wide.
The area of the pool is 12(6) = 72 m².
Adding a walkway of unknown width, x, around all 4 sides of the pool increases the width by 2x and the length by 2x; thus the area of the entire pool and walkway together would be given by
(12+2x)(6+2x)
We know that the area of just the walkway is 9 m² less than the area of the pool. This means that:
(12+2x)(6+2x)-72 = 72-9
Multiplying through we have:
12*6+12*2x+2x*6+2x*2x - 72 = 63
72 + 24x + 12x + 4x² - 72 = 63
24x + 12x + 4x² = 63
36x + 4x² = 63
Writing in standard form we have:
4x² + 36x = 63
We want to set it equal to 0 to solve, so subtract 63 from both sides:
4x² + 36x - 63 = 63 - 63
4x² + 36x - 63 = 0
Using the quadratic formula,

Since a negative width makes no sense, the walkway is 1.5 m wide.
Answer:
c=11d+1
Step-by-step explanation:
First, you should know how will 1 lesson cost. Eventually, 1 lesson costs $11.
c is for the cost.
11 is for the cost of 1 lesson.
d is for the lessons
1 represents (1 lesson, which costs $11)