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NeTakaya
3 years ago
10

a rectangular feild is 16metre long and 10 metre wide.there is a uniform width all around it having an area of 120metre square​

Mathematics
1 answer:
Anni [7]3 years ago
5 0

Answer:

2 metre

Step-by-step explanation:

let the width around the field be x metre

then (16+2x)(10+2x)-16×10=120

160+32x+20x+4x²-160=120

4x²+52x-120=0

or x²+13x-30=0

x²+15x-2x-30=0

x(x+15)-2(x+15)=0

(x+15)(x-2)=0

either x+15=0,

x=-15 (Rejected being negative)

or x-2=0

x=2 metre

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I need a lot of help with practice problems, I am not understanding math right now. Please help!!!!!! Will give brainliest!!
34kurt

Answer:

1. 18 (sqrt21 - sqrt2a)

2. 3

3. x^m/n

4. (5x^4√10)/(√2x)

5. x = -2 or -6

6. x = 30

Step-by-step explanation:

Number 1

3^3sqrt21 - 6^3sqrt2a

3 * 6 * sqrt21 - sqrt2a

18 (sqrt21 - sqrt2a)

Number 2

3^1/2 * 3^1/2 =

3^1/2+1/2 =

3^1 =

3

Number 3

^nsqrtx^m =

x^m/n

Number 4

(√250x^16)/(√2x) =

(√25 * 10 * x^16)/√(2x )=

(5x^4√10)/(√2x)

Number 5

√2x + 13 - 5 = x

√2x + 13 = x + 5

square both side to take away the sqrt sign

(√2x + 13)^2 = (x + 5)^2

expand the equation on the RHS

2x + 13 = x(x+5) + 5(x+5)

2x+13 = x^2 + 10x +25

substract 13 from both sides

2x = x^s + 10x +12

subtract 2x from both sides

0 = x^2 +8x + 12

Factorize equation

x^2 + 6x +2x + 12 = 0

x(x+6) + 2(x+6) = 0

(x+2)(x+6) = 0

x = -2 or -6

Number 6

3 ^5sqrt(x+2)^3 + 3 = 27

subtract 3 from both sides

3 ^5sqrt(x+2)^3  = 27 - 3

3 ^5sqrt(x+2)^3  = 24

divide through by 3

^5sqrt(x+2)^3  = 8

square both sides by 5 to take away the 5th root sign

(x+2)^3  = (8)^5

(x+2)^3  = 32,768

take the cube root of both sides to take away the ^3

x+2 = ^3sqrt 32,768

x+2 = 32

x = 32 - 2

x = 30

3 0
4 years ago
Read 2 more answers
A grocer wants to mix two kinds of candy. One kind sells for $1.15 per pound, and the other sells for
scZoUnD [109]

Hey there!

This grocer is mixing two kinds of coffee. I always love the smell of coffee!

We will say that x sells for $1.15 per pound and y sells for $2.75 per pound.

Altogether there are 24 pounds of coffee he is selling.

The algebraic equation would be x + y = 24

At $1.30 per pound, he will make 24 * $1.30 = $31.2

So, how many of the x and y kinds of coffee should he use to make the $1.30 per pound mixture which will net him $31.2?

The algebraic equation would be 1.15x + 2.75y = 31.2

We now have two equations :

x+y = 24

1.15x + 2.75y = 31.2

Substituting x= 24 -y in the second equation gives us

1.15(24-y) + 2.75y = 31.2

27.6 - 1.15y + 2.75y = 31.2

27.6 + 1.6y = 31.2

1.6y = 31.2 - 27.6

0.3y= 3.6

y= 2.25

x + y = 24

x + 2.25 = 24

x = 24 -2.25

x = 21.75

If y=2.25, then x= 21.75 as well.

So, he will use 21.75 pounds of the $1.15 per/lb one and another 2.25 pounds of the $2.75per/lb one.

~Done~

6 0
2 years ago
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nadezda [96]

4yn +7k=6 for y

3/7k=6

7 0
3 years ago
Kenneth is inviting people to his parents' anniversary party and wants to stay at or below his budget of $6,000 for the food. Th
ohaa [14]
X= the number of adults
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Knenneth can´t afford more than $6000.

Therefore, the ineguality will be:
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3 years ago
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Answer:

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