1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
marin [14]
2 years ago
12

The contents of Dana's box of muffins is shown.

Mathematics
1 answer:
TiliK225 [7]2 years ago
6 0
3/5 would be the answer because every 3 banana nut here is 5 corn
You might be interested in
This is geometry, I need help! Please and thanks!!
denis23 [38]

Problem 8

Answer: angle LSO and angle MSN

--------------

Explanation:

Vertical angles form when we intersect two line segments, lines, or rays. Vertical angles are opposite one another and they are always congruent.

=============================================

Problem 9

Answer: angle LMS and angle SMN

--------------

Explanation:

Adjacent angles share a common line, line segment, or ray. Think of two adjacent rooms sharing a common wall between them. In the case of the answer above, the two angles share the common segment SM (note how S and M are part of LMS and SMN)

When it comes to naming angles, the middle letter is always the vertex of the angle. This is the hinge so to speak. Or you could picture a pair of scissors. For angle LMS, the arms LM and SM are the two blades of the scissors while point M is where the blades meet.

=============================================

Problem 10

Answer: angle LSM and angle MSN

--------------

Explanation:

Same idea as problem 9. Now we're making S the middle letter. Something like angle LSM is the same as angle MSL.

In this case, the two adjacent angles form a straight line. We consider these two angles a linear pair.

=============================================

Problem 11

Answer: angle LSO and angle OSN

--------------

Explanation:

The term linear pair was discussed back in problem 10. So you could list those two angles again, or you could go with another pair as shown above. All that matters is that they are adjacent angles and they are supplementary angles (they add to 180 degrees). There are many possible answers.

Something like the angle pair angle LOS and angle NOS are adjacent angles, but they aren't supplementary. So we don't meet the condition of a linear pair here.

5 0
3 years ago
(◟ᅇ)◜Please Help Asap, Tysm!
d1i1m1o1n [39]

Answer:

Step-by-step explanation:

3 hope this helps :))

7 0
3 years ago
Read 2 more answers
How many doughnuts are in 1/3 dozen? Please help meeee!!!!
Eva8 [605]
There are 4 doughnuts in 1/3 of a dozen
6 0
3 years ago
Read 2 more answers
6. Sales associates at a local clothing
RSB [31]

Answer:

ask the internet this question sorry not being rude its becausd no ones answered it

6 0
2 years ago
The integral of (5x+8)/(x^2+3x+2) from 0 to 1
Gnom [1K]
Compute the definite integral:
 integral_0^1 (5 x + 8)/(x^2 + 3 x + 2) dx

Rewrite the integrand (5 x + 8)/(x^2 + 3 x + 2) as (5 (2 x + 3))/(2 (x^2 + 3 x + 2)) + 1/(2 (x^2 + 3 x + 2)):
 = integral_0^1 ((5 (2 x + 3))/(2 (x^2 + 3 x + 2)) + 1/(2 (x^2 + 3 x + 2))) dx

Integrate the sum term by term and factor out constants:
 = 5/2 integral_0^1 (2 x + 3)/(x^2 + 3 x + 2) dx + 1/2 integral_0^1 1/(x^2 + 3 x + 2) dx

For the integrand (2 x + 3)/(x^2 + 3 x + 2), substitute u = x^2 + 3 x + 2 and du = (2 x + 3) dx.
This gives a new lower bound u = 2 + 3 0 + 0^2 = 2 and upper bound u = 2 + 3 1 + 1^2 = 6: = 5/2 integral_2^6 1/u du + 1/2 integral_0^1 1/(x^2 + 3 x + 2) dx

Apply the fundamental theorem of calculus.
The antiderivative of 1/u is log(u): = (5 log(u))/2 right bracketing bar _2^6 + 1/2 integral_0^1 1/(x^2 + 3 x + 2) dx

Evaluate the antiderivative at the limits and subtract.
 (5 log(u))/2 right bracketing bar _2^6 = (5 log(6))/2 - (5 log(2))/2 = (5 log(3))/2: = (5 log(3))/2 + 1/2 integral_0^1 1/(x^2 + 3 x + 2) dx

For the integrand 1/(x^2 + 3 x + 2), complete the square:
 = (5 log(3))/2 + 1/2 integral_0^1 1/((x + 3/2)^2 - 1/4) dx

For the integrand 1/((x + 3/2)^2 - 1/4), substitute s = x + 3/2 and ds = dx.
This gives a new lower bound s = 3/2 + 0 = 3/2 and upper bound s = 3/2 + 1 = 5/2: = (5 log(3))/2 + 1/2 integral_(3/2)^(5/2) 1/(s^2 - 1/4) ds

Factor -1/4 from the denominator:
 = (5 log(3))/2 + 1/2 integral_(3/2)^(5/2) 4/(4 s^2 - 1) ds

Factor out constants:
 = (5 log(3))/2 + 2 integral_(3/2)^(5/2) 1/(4 s^2 - 1) ds

Factor -1 from the denominator:
 = (5 log(3))/2 - 2 integral_(3/2)^(5/2) 1/(1 - 4 s^2) ds

For the integrand 1/(1 - 4 s^2), substitute p = 2 s and dp = 2 ds.
This gives a new lower bound p = (2 3)/2 = 3 and upper bound p = (2 5)/2 = 5:
 = (5 log(3))/2 - integral_3^5 1/(1 - p^2) dp

Apply the fundamental theorem of calculus.
The antiderivative of 1/(1 - p^2) is tanh^(-1)(p):
 = (5 log(3))/2 + (-tanh^(-1)(p)) right bracketing bar _3^5


Evaluate the antiderivative at the limits and subtract. (-tanh^(-1)(p)) right bracketing bar _3^5 = (-tanh^(-1)(5)) - (-tanh^(-1)(3)) = tanh^(-1)(3) - tanh^(-1)(5):
 = (5 log(3))/2 + tanh^(-1)(3) - tanh^(-1)(5)

Which is equal to:

Answer:  = log(18)
5 0
3 years ago
Other questions:
  • A gallon of water a room temperature Waze about 8.35 pounds Lena put 4.5 gallons in a bucket how much does the water weight
    9·2 answers
  • Find x and round to nearest tenth
    9·1 answer
  • What is this answer???
    13·1 answer
  • Someone talk to me bout anythang
    8·1 answer
  • I NEED HELP ASAP PLEASE​
    13·1 answer
  • Find the volume of the following shapes. Round to tenths and don’t forget the units. Show your work!
    6·1 answer
  • Which expression is equivalent to: 3^2 x 3/ 3^4
    5·1 answer
  • What is -1/2-(5/9) in the simplest form
    12·2 answers
  • The number of guests, g, coming for dinner<br> is not 8
    11·1 answer
  • If point D is placed on AC, how will the measure of
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!