Answer:
See Explanation
Step-by-step explanation:
Your question is incomplete, as the equations or graph or table(s) were not given.
However, I'll give a general way of solving this.
Take for instance, the equations are:


To do this, we start by equating both equations.

i.e.

Collect Like Terms

Take LCM


Cross Multiply


Make x the subject

Substitute 3/4 for x in 



Hence:

The answer is B. 45m/s north
The three points A,B,C are all points on this circle.
Each point is then equal distance from the center, that distance being the radius of the circle.
Using the distance formula, we can find the center of the circle (x,y):

Plugging in points A and B into distance formula, then setting them equal to each other gives:

Right away we can cancel out the x terms leaving:

Expand Left side and Solve for y:


Plug in points B and C as before:

Here we can cancel the y-terms.
Expand and solve for x:



Therefore the center of the circle is the point (6,3)
Answer:
120
Step-by-step explanation:
Just add the 20 back to 40 and times by 2
40 + 20 = 60
60 * 2 = 120