Sue is selling chocolate chip cookies for

Ruby conducted a survey and found that 5/6 of her classmates have a pet and 2/3 of them are dogs what fraction of her classmates

lina2011 [118]

This is how I would solve it, I would act as if there were 36 people in the class.
36÷6=6×5=30
30÷3=10×2=20
20/36=10/18=5/9
You could also try another number such as 24;
24×(5÷6)=20
20×(2/3)=13.3(3 repeating)
13.333/24=5/9
5/9 people have dogs.
Tell me if this helps.

7 0

3 years ago

Find the (a) mean, (b) median, (c) mode, and (d) midrange for the data and then (e) answer the given question. Listed below

mafiozo [28]

Answer:

a) $\bar X = 369.62$

b) $Median=175$

c) $Mode =450$

With a frequency of 4

d) $MidR= \frac{Max +Min}{2}= \frac{49+3000}{2}= 1524.5$

<u>e)</u> $s = 621.76$

And we can find the limits without any outliers using two deviations from the mean and we got:

$\bar X+2\sigma = 369.62 +2*621.76 = 1361$

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case

Step-by-step explanation:

We have the following data set given:

49 70 70 70 75 75 85 95 100 125 150 150 175 184 225 225 275 350 400 450 450 450 450 1500 3000

Part a

The mean can be calculated with this formula:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

Replacing we got:

$\bar X = 369.62$

Part b

Since the sample size is n =25 we can calculate the median from the dataset ordered on increasing way. And for this case the median would be the value in the 13th position and we got:

$Median=175$

Part c

The mode is the most repeated value in the sample and for this case is:

$Mode =450$

With a frequency of 4

Part d

The midrange for this case is defined as:

$MidR= \frac{Max +Min}{2}= \frac{49+3000}{2}= 1524.5$

Part e

For this case we can calculate the deviation given by:

$s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And replacing we got:

$s = 621.76$

And we can find the limits without any outliers using two deviations from the mean and we got:

$\bar X+2\sigma = 369.62 +2*621.76 = 1361$

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case

5 0

3 years ago

What is the median of this data set?

bazaltina [42]

Answer:

14

Step-by-step explanation:

Because the median is the middle number when the data set is in order least to greatest so you already have it in least to greatest so thank you for helping me.

and for extra just in case.

Mean=16.222

the mean= the average of the data set

Mode is 13,14

The mode is the number that appears the most in a data set and 13 and 14 appear twice.

Your range is=13

Range is the highest number subtracting the lowest number so 24 -11 which =13

Minimum is 11 because the minimum is the lowest number in data set..

Maximum is 24

Maximum is the highest number in the data set.

I hope this helps have a awesome day:)

7 0

2 years ago

Read 2 more answers

One-half of one-seventh of T equals one-third of one-fifth of 90. What is the value of T

butalik [34]

Answer:

Step-by-step explanation:

This is the equation. Read it carefully.

1/2 * 1/7 T = 1/3 * 1/5 * 90 Reduce

(1/14) * T = 1/15 * 90

1/15 * 90 = 6

(1/14)*T = 6 Multiply both sides by 14

T = 14 * 6

T = 84

3 0

2 years ago

Perfectly poped sell a variety of popcorn flavor in large,decorated tubs.if jenna order 36 mathching tubs containing 216 gallons

Lena [83]

6 gallons, if there is 216 gallons in 36 tubs you have to take 216÷36 to get 6 gallons. To check your answer you can take 36 × 6

4 0

3 years ago

Read 2 more answers