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nordsb [41]
3 years ago
7

Write 100 more than 234641

Mathematics
1 answer:
WINSTONCH [101]3 years ago
4 0
234741



whaaaaaaaaaaaaaaaat
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What value of makes this equation true? =92 =60 =38 =76
HACTEHA [7]

Answer:

y = 60

Step-by-step explanation:

Given

22 + 54 = y + 16 , that is

76 = y + 16 ( subtract 16 from both sides )

60 = y

6 0
2 years ago
Explain the mistake made
olga55 [171]
In the second step you should have subtracted the 2x to move it to the other or side of the equals sign
8 0
3 years ago
Identify the real and imaginary parts of the complex number. -5 + 6i
Genrish500 [490]
-5 is the real part and 6i is the imaginary part. This can be determined by looking which number has the "i" attached to it. 
4 0
3 years ago
PLEASE HELP ;)<br> Who did it right?<br><br> Find the slope of the line perpendicular to 2x+3y=8
levacccp [35]

Answer:

Marissa.

Step-by-step explanation:

To find perpendicular slope you basically take the slope of the given line and reverse whatever sign it had previously. (If it was negative, it would become positive. If it was positive it would become negative.)

By doing -A/B it make the previous slope negative.

Brandon only flipped the fraction which would just result in the slope being slightly steeper, or in this case, less steep than the previous line, rather than making it perpendicular.

Hope this helps! Stay safe and if you have any questions feel free to ask!

6 0
2 years ago
Triangle JKL has vertices J(2,5), K(1,1), and L(5,2). Triangle QNP has vertices Q(-4,4), N(-3,0), and P(-7,1). Is (triangle)JKL
Tems11 [23]

Answer:

Yes they are

Step-by-step explanation:

In the triangle JKL, the sides can be calculated as following:

  • J(2;5); K(1;1)

             => JK = \sqrt{(1-2)^{2} + (1-5)^{2}  } = \sqrt{(-1)^{2}+(-4)^{2}  } = \sqrt{1+16}=\sqrt{17}

  • J(2;5); L(5;2)

             => JL = \sqrt{(5-2)^{2} + (2-5)^{2}  } = \sqrt{3^{2}+(-3)^{2}  } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}

  • K(1;1); L(5;2)

             =>  KL = \sqrt{(5-1)^{2} + (2-1)^{2}  } = \sqrt{4^{2}+1^{2}  } = \sqrt{1+16}=\sqrt{17}

In the triangle QNP, the sides can be calculate as following:

  • Q(-4;4); N(-3;0)

             => QN = \sqrt{[-3-(-4)]^{2} + (0-4)^{2}  } = \sqrt{1^{2}+(-4)^{2}  } = \sqrt{1+16}=\sqrt{17}

  • Q (-4;4); P(-7;1)

   => QP = \sqrt{[-7-(-4)]^{2} + (1-4)^{2}  } = \sqrt{(-3)^{2}+(-3)^{2}  } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}

  • N(-3;0); P(-7;1)

             =>  NP = \sqrt{[-7-(-3)]^{2} + (1-0)^{2}  } = \sqrt{(-4)^{2}+1^{2}  } = \sqrt{16+1}=\sqrt{17}

It can be seen that QPN and JKL have: JK = QN; JL = QP; KL = NP

=> They are congruent triangles

7 0
3 years ago
Read 2 more answers
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