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leva [86]
3 years ago
12

The statement tan theta= -12/5, csc theta=-13/12, and the terminal point determained by theta is in quadrant two

Mathematics
2 answers:
Alecsey [184]3 years ago
7 0

Answer:

cannot be true because csc theta is greater than zero in quadrant 2

Step-by-step explanation:

apex users good luck

Lisa [10]3 years ago
6 0

Solution:

tan (theta)=\frac{-12}{5}=\frac{\text{Perpendicular}}{\text{Base}}

Cosec(theta)=\frac{-13}{12}=\frac{\text{Hypotenuse}}{\text{Altitude}}

In right Triangle,

using Pythagoras theorem

(Hypotenuse)²= (Base)² + (Altitude)²

⇒ (Hypotenuse)²= (12)² + (5)²

⇒Hypotenuse= √(144 +25)

⇒Hypotenuse= 13 cm

As, the value of tan(theta)=\frac{-12}{5} is true if Theta lies in Second Quadrant, but it is not true for Cosec(theta)=\frac{-13}{12}  ,if theta lies in second Quadrant, because value of Cosec(theta) is positive in second Quadrant ,irrespective of fact that Terminal side lies in Second Quadrant.

So,  The statement tan (theta)= -12/5, and Cosec (theta)=-13/12, and the terminal point determined by theta is in quadrant two is Incorrect.

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