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3 years ago

11

Catherine is going cycling with 3 friends. They take 2 L of water for each person. At the end of the day they have 0.8 L of wate

r left. How much water have they drunk?

1 answer:

andreyandreev [35.5K]3 years ago

5 0

Answer:5.2L

Step-by-step explanation:

They take 2L for 3 friends.

2 times 3=6L

Athe end of the day they have 0.8L left.

6L-0.8L=5.2L

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Solve the absolute value equation for <br> |r-6|=3

Volgvan

The solutions would be 3 and 9

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3 years ago

Read 2 more answers

A data mining routine has been applied to a transaction dataset and has classified 88 records as fraudulent (30 correctly so) an

Firlakuza [10]

Answer:

The classification matrix is attached below

Part a

The classification error rate for the records those are truly fraudulent is 65.91%.

Part b

The classification error rate for records that are truly non-fraudulent is 96.64%

Step-by-step explanation:

The classification matrix is obtained as shown below:

The transaction dataset has 30 fraudulent correctly classified records out of 88 records, that is, 30 records are correctly predicted given that an instance is negative.

Also, there would be 88 - 30 = 58 non-fraudulent incorrectly classified records, that is, 58 records are incorrectly predicted given that an instance is positive.

The transaction dataset has 920 non-fraudulent correctly classified records out of 952 records, that is, 920 records are correctly predicted given that an instance is positive.

Also, there would be 952 - 920 = 32 fraudulent incorrectly classified records, that is, 32 records incorrectly predicted given that an instance is negative.

That is,

Predicted value

Active value Fraudulent Non-fraudulent

Fraudlent 30 58

non-fraudulent 32 920

The classification matrix is obtained by using the information related to the transaction data, which is classified into fraudulent records and non-fraudulent records.

The error rate is obtained as shown below:

The error rate is obtained by taking the ratio of $\left( {b + c} \right)(b+c)$ and the total number of records.

The classification matrix is, shown above

The total number of records is, $30 + 58 + 32 + 920 = 1,040$

The error rate is,

$\begin{array}{c}\\{\rm{Error}}\,{\rm{rate}} = \frac{{b + c}}{{{\rm{Total}}}}\\\\ = \frac{{58 + 32}}{{1,040}}\\\\ = \frac{{90}}{{1,040}}\\\\ = 0.0865\\\end{array}$

The percentage is $0.0865 \times 100 = 8.65$

(a)

The classification error rate for the records those are truly fraudulent is obtained by taking the rate ratio of b and $\left( {a + b} \right)(a+b)$ .

The classification error rate for the records those are truly fraudulent is obtained as shown below:

The classification matrix is, shown above and in the attachment

The error rate for truly fraudulent is,

$\begin{array}{c}\\FP = \frac{b}{{a + b}}\\\\ = \frac{{58}}{{30 + 58}}\\\\ = \frac{{58}}{{88}}\\\\ = 0.6591\\\end{array}$

The percentage is, $0.6591 \times 100 = 65.91$

(b)

The classification error rate for records that are truly non-fraudulent is obtained by taking the ratio of d and $\left( {c + d} \right)(c+d)$ .

The classification error rate for records that are truly non-fraudulent is obtained as shown below:

The classification matrix is, shown in the attachment

The error rate for truly non-fraudulent is,

$\begin{array}{c}\\TP = \frac{d}{{c + d}}\\\\ = \frac{{920}}{{32 + 920}}\\\\ = \frac{{920}}{{952}}\\\\ = 0.9664\\\end{array}$

The percentage is, $0.9664 \times 100 = 96.64$

6 0

3 years ago

If I have 7 button down shirts, 5 pairs of pants and 3 pairs of shoes that I can wear to work then how many different outfits ca

34kurt

105 different outfits can wear on an individual day

<em><u>Solution:</u></em>

I have 7 button down shirts, 5 pairs of pants and 3 pairs of shoes that I can wear to work

To find: Number of different outfits can I wear on an individual day

First he has to decide on a pair of pants and he has 5 different choices

For each of those choices he has a choice of 7 different button down shirts, so that gives him 5 x 7 = 35 different pant/shirt combinations

For each of those 35 different pant/shirt combinations, he has 3 pairs of shoes he could select, so altogether he has 35 x 3 = 105 different outfits

In short we can say,

different outfits = 7 x 5 x 3 = 105

So there 105 different outfits can wear on an individual day

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3 years ago

Enter the correct number word to complete the conversion. 1 milliampere = one ? of an ampere

Lerok [7]

Answer:

One milliampere is equal to 0.001 ampere.

Step-by-step explanation:

Mili, refers to thousandth. (for example, millimeter or milliliter.)

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3 years ago

Solve for m -20+14m=10m+16

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-20+14m=10m+16
-10m. -10m
-20+4m=16
+20. +20
4m=36
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3 years ago