Answer:
The number of seniors who scored above 96% is 1.
Step-by-step explanation:
Consider the provided information.
Two percent of all seniors in a class of 50 have scored above 96% on an ext exam.
Now we need to find the number of seniors who scored above 96%
For this we need to find the two percent of 50.
2% of 50 can be calculated as:
Hence, the number of seniors who scored above 96% is 1.
If the mean is 20.8, one standard deviation each way is adding and subtracting 3.1, so 17.7 and 23.9 (68% of values)
Two standard deviations adding and subtracting 3.1*2 = 6.2, or 14.6 and 27.
Three standard deviations is 11.5 and 30.1
So we have
11.5 - 14.6 - 17.7 - 20.8 - 23.9 - 27 - 30.1
Going left to 11.5 is 3 standard deviations out, so 99.7/2 = 49.85%
Going right to 27 is 2 standard deviations out, so 95/2 = 47.5%
Add those two % to get 97.32%
This is hard to do without a picture so I hope that helps!
Answer:
A
Step-by-step explanation:
V= BxHxL divided by 2
6x9x21= 1,134
divided by 2 equals 567yd
G-(-43)=19
g+43=19
g=19-43
g=-24
B.
