-3x - 4y - 2z = 0
x + 3y + 2z = 1
-2x - y = 1
-4x - 4y - 2z = 10
3x + 4y +2z= 0
-x = 10. x = -10
-2(-10) - y = 1
20 - y = 1
-y = -19
y = 19
-10 + 3(19) + 2z = 1
-10 + 57 + 2z = 1
47 + 2z = 1
2z = -46
z= -23
check: 2(-10)+2(19)-23=-5
-20+38-23=-5
-43+38=-5
-5=-5
X= number of dimes
x+6= number of quarters
5(x+6)= number of nickels
$5.40= 540 cents
Add the number of each coin and set it equal to the total in cents.
x + (x + 6) + 5(x + 6)= $5.40
multiply 5 by parentheses; change dollar total to cents
x + (x + 6) + (5 * x) + (5 * 6)= 540
x + (x + 6) + 5x + 30= 540
combine like terms
7x + 36= 540
subtract 36 from both sides
7x= 504
divide both sides by 7
x= 72 dimes
x + 6= 78 quarters
5(x + 6)= 390 nickels
CHECK
72 + 78 + 390= 540
540= 540
ANSWER: There are 72 dimes, 78 quarters and 390 nickels.
Hope this helps! :)
Answer:49
Step by step is 56÷16=3.5
14x3.5=49
Find the distance between the points t(13, 1.6)t(13, 1.6) and v(5.4, 3.7)v(5.4, 3.7).
1
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The distance between any 2 points P(a,b) and Q(c,d) in the coordinate plane, is given by the formula:
Thus the distance between points t(13, 1.6) and v(5.4, 3.7) is found using the formula as:
Notice that 38 and 52 make a total of 90
sinA=cos(90-A)
sin38=cos52, therefore the answer is zero
