Step-by-step explanation:
the correct answer is C because the measurementor an angle cannot be under 72 :)
Multiplying is repeated addition, and a positive times a negative equals a negative, so you're only going to be needing the side with negatives that finally get to zero. First, find 0, then take it 6 numbers back, -6. repeat the step until you have three loops. It should equal -18. Hope this helps :)
Answers with explanations:
Problem 2-
First we have to insert our numbers into the equation. So we would have
l2l-l-7l
The ll bars mean to find the absolute value. Absolute value is how many spaces it is between that number and zero. So we can simply this to
2-7=-5
Problem 3-
First, we have to insert our numbers into the problem.
2(-2)^3(3)
Using PEMDAS or order of operations, we solve the exponent first and simplify from there
2(-8)(3)
(-16)(3)
(-48)
The answer is -48
Problem 4-
Again, we have to input the numbers into the equation.
(4^2-4(-3))/2
(16-4(-3))/2
(16+12)/2
(28)/2
14
The answer is 14
Problem 5-
(3)(-1)-(-1^2)
(3)(-1)-(1)
-3-1
-4
The answer is -4
Problem 7-
l-3-4l- -3^2
l-3-4l- +9
l-7| - +9
7-+9
-2
The answer is -2
Problem 8-
3(-3)^2-4|-3|+6
3(9)-4|-3|+6
27-4|-3|+6
27-12+6
21
128 is the total amount. Because she has megabytes negative
<span>Answer:
In an arithmetic sequence, whose first term is a and difference between a term and its preceding term is d,
the nth term is a+(nâ’1)d and sum of first n terms is n2(2a+(nâ’1)d)
Hence 6th term will be a+5d=8 and 10th term will be a+9d=13
Subtracting first from second, 4d=5 or d=1.25
and a=8â’5â‹…1.25=8â’6.25=1.75
Hence sum of first four terms is
42â‹…(2â‹…1.75+3â‹…1.25)=2â‹…(3.5+3.75)=2â‹…7.25=14.50</span>
