Tell me what is the equation for equation 1 and 2

I WILL GIVE BRAINLIEST

adelina 88 [10]

Answer: 2x - 1 (+x) =19

4 0

3 years ago

40 liters is equal to

Julli [10]

Really it depends on what your trying to match it too

But it can be equal to
~10.5669 U.S liquid gallons
~40,000 milliliters
~169.07 cups
~84.5351 pints

8 0

3 years ago

Which explanation provides the best real-world scenario of the graph? If an object is dropped from a height of 38 feet, the func

ikadub [295]

The equation that models the movement of the object is:
$h (t) = (1/2) * (a) * (t ^ 2) + v0 * t + h0
$
Where,
t: time
a: acceleration due to gravity
v0: initial speed
h0: initial height
Suppose that the object falls with zero initial velocity and from a height of 38 feet.
The equation that models the problem is:
$h (t) = -16t ^ 2 + 38
$
Answer:
If an object is dropped from a height of 38 feet, the function h (t) = -16t2 + 38 gives the height of the object after seconds

5 0

3 years ago

A simplified model for the movement of the price of a stock supposes that on each day the stock’s price either moves up 1 unit w

DanielleElmas [232]

Answer:

(a) The probability that after 2 days the stock will be at its original price is

$P_a=2p(1-p)$

(b) The probability that after 3 days the stock’s price will have increased by 1 unit is

$P_b=3p^2(1-p)$

(c) Given that after 3 days the stock’s price has increased by 1 unit, the probability that it went up on the first day is

$P=2/3$

Step-by-step explanation:

(a) What is the probability that after 2 days the stock will be at its original price?

For the price of the stock to be in its original price, there are two ways it can happen:

1) the price increases the first day by one unit and decreases by one unit the second day. The probability of this event is P=p*(1-p).

2) the price decreases the first day by one unit and increases by one unit the second day. The probability of this event is P=(1-p)p.

The probability that after 2 days the stock will be at its original price is the sum of the probability of this two events:

$P=P_1+P_2=p(1-p)+(1-p)p=2p(1-p)$

(b) What is the probability that after 3 days the stock’s price will have increased by 1 unit?

For this event to happen (one unit increase in 3 days), it must have happened 2 increases in price and 1 decrease.

There are 3 possible ways of this to happen:

1) decrease in the first day.

2) decrease in the second day.

3) decrease in the third day.

Each one ot this 3 events has the same probability $P_i=p^2(1-p)$ .

So the probability that after 3 days the stock’s price will have increased by 1 unit is equal to the sum of the probabilities of this events:

$P=P_1+P_2+P_3=3p^2(1-p)$

(c) Given that after 3 days the stock’s price has increased by 1 unit, what is the probability that it went up on the first day?

According to the answer (c), there are 3 events where the price has increase by one unit after 3 days, each one with equal probability $P_i=p^2(1-p)$ .

Of these 3 events, there are 2 that have an increase in the first day. So we can conclude that, if the events have the same probability, the probability of the increase in the first day, given that the price has increased by one unit in 3 days, is P=2/3.

8 0

4 years ago

Please help me asap for brainlist its for final exams

kumpel [21]

Answer: y = — $\frac{1}{2}$ x + 3

Step-by-step explanation:

The line crosses the y-axis at the point (0,3), making its y-intercept be +3.

The line is going downwards left to right, giving it a negative slope.

The line's slope is — $\frac{1}{2}$ because it is negative and it goes down 1, over 2.

Therefore, the line's equation is y = — $\frac{1}{2}$ x + 3

6 0

2 years ago