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LUCKY_DIMON [66]
3 years ago
14

Find the measure of the line segment AD

Mathematics
2 answers:
lidiya [134]3 years ago
5 0

Answer:

18

Step-by-step explanation:

Since AB ≅ BD that means they equal the same

2x + 3 = 5x - 6

First: subtract 2x from both sides thus giving you

3 = 3x - 6

Second: add six to both sides, divide by three and simplify

9 = 3x  

\frac{9}{3} = \frac{3x}{3}  

x = 3

Lastly: substitute values of x and simplify

AB = 2(3) + 3 = 9

BD = 5(3) - 6 = 9

9 + 9 = 18

AD = 18

vesna_86 [32]3 years ago
4 0
The measure of segment AB is 2x-3 and the measure of segment BD is 5x-6.
If you want to find the measure of segment AD you have to add up AB and BD

So 2x-3+5x-6, combine like terms 2x+5x equals 7x and -3-6 equals -9, so the measure of segment AD is 7x-9
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What is the logarithmic formula 10000= 625/8*2^t ?
Elodia [21]

9514 1404 393

Answer:

     log(128) = t·log(2)

Step-by-step explanation:

You can take logarithms the way the formula is, or you can simplify it first.

<u>As is</u>

  log(10000) = log(625) -log(8) +t·log(2)

__

<u>Simplified</u>

  8·10000/625 = 2^t . . . . . multiply by 8/625

  128 = 2^t

  log(128) = t·log(2)

_____

Solution:

  t = log(128)/log(2) = 7

8 0
3 years ago
the flight of an aircraft from toronto to montrel can be modelled by he relation h=-2.5t2+200t where t is the time, in minutes,
musickatia [10]
So far, this is shaping up to be a very interesting and engaging exercise. Now, what do you want done with the model ? To put it in other words, what is the question ? ? (Other than the fact that no real flight can fit this model.)
6 0
3 years ago
Camryn practices the trumpet every 11th day and the flute every 3rd day. Camryn practiced both the trumpet and the flute today.
QveST [7]

Answer: 33 days.


Step-by-step explanation:

Given :- Camryn practices the trumpet every 11th day and the flute every 3rd day.

Camryn practiced both the trumpet and the flute today.  

To find the number of days until Camryn practices the trumpet and flute again in the same day, we need to find the least common multiple (L.C.M.) of 11 and 3.

As they both are co-prime numbers thus its L.C.M.= 11×3=33

Therefore, Camryn practices the trumpet and flute again in the same day after 33 days.

4 0
4 years ago
A car drives east along a road at a constant speed of 46 miles per hour. At 4:00 P.M., a truck is 264 miles away, driving west a
sveticcg [70]

Answer:

The speed of the truck is 42 mph

Step-by-step explanation:

we know that

The speed is equal to divide the distance by the time

Let

s -----> the speed in miles per hour

d ----> the distance in miles

t ----> the time in hours

s=\frac{d}{t}

d=s(t)

step 1

Find out the distance traveled by the car at 7:00 P.M

we have

s=46\ \frac{mi}{h}

t=7:00 P.M-4:00 P.M=3\ h

d=s(t)

substitute the values

d=46(3)=138\ mi

step 2

Find out the speed of the truck

we know that

At 7:00 P.M the distance is equal to

d=264-138=126\ mi

t=7:00 P.M-4:00 P.M=3\ h

substitute

s=\frac{126}{3}

s=42\ \frac{mi}{h}

7 0
3 years ago
Need in depth explanation please​
zysi [14]

Answer:

Y = 18

X = 9

Step-by-step explanation:

all the steps are in the picture. comment if you have any doubts.

4 0
2 years ago
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