9514 1404 393
Answer:
log(128) = t·log(2)
Step-by-step explanation:
You can take logarithms the way the formula is, or you can simplify it first.
<u>As is</u>
log(10000) = log(625) -log(8) +t·log(2)
__
<u>Simplified</u>
8·10000/625 = 2^t . . . . . multiply by 8/625
128 = 2^t
log(128) = t·log(2)
_____
Solution:
t = log(128)/log(2) = 7
So far, this is shaping up to be a very interesting and engaging exercise. Now, what do you want done with the model ? To put it in other words, what is the question ? ? (Other than the fact that no real flight can fit this model.)
Answer: 33 days.
Step-by-step explanation:
Given :- Camryn practices the trumpet every 11th day and the flute every 3rd day.
Camryn practiced both the trumpet and the flute today.
To find the number of days until Camryn practices the trumpet and flute again in the same day, we need to find the least common multiple (L.C.M.) of 11 and 3.
As they both are co-prime numbers thus its L.C.M.= 11×3=33
Therefore, Camryn practices the trumpet and flute again in the same day after 33 days.
Answer:
The speed of the truck is 42 mph
Step-by-step explanation:
we know that
The speed is equal to divide the distance by the time
Let
s -----> the speed in miles per hour
d ----> the distance in miles
t ----> the time in hours


step 1
Find out the distance traveled by the car at 7:00 P.M
we have



substitute the values

step 2
Find out the speed of the truck
we know that
At 7:00 P.M the distance is equal to


substitute


Answer:
Y = 18
X = 9
Step-by-step explanation:
all the steps are in the picture. comment if you have any doubts.