Does (-1, 5) make the inequality y < 3x + 8 true?
2 answers:
Answer:
<u>(–1, 5) does NOT make </u><u><em>y</em></u><u> < 3</u><u><em>x</em></u><u> + 8 true.</u>
Step-by-step explanation:
First, let's substitute the values into the inequality. It's the one way to see if the point (–1, 5) is in the range of <em>y</em> < 3<em>x</em> + 8
5 ≟ 3(–1) + 8
5 ≟ 8 – 3
5 = 5 ✘
This means (–1, 5) does NOT make the inequality <em>y</em> < 3<em>x</em> + 8 true.
Answer:
No
Step-by-step explanation:
as X=-1. and y=5
according to this y<3x+8
which means 5< 3*-1 +8
5<-3+8
5<5
which is not true.. as 5=5
You might be interested in
Solve first equation for y:
5x+y=10
y=10-5x. Plug this equation into second equation
-x-(10-5x)=-2
-x-10+5x=-2
4x=8
x=2 (plug x into first equation)
5(2)+y=10
y=0
Answer:
7/23
Step-by-step explanation:
.93 would have to be the answer because you do the regular calculations, then you divide to find y.
7π/12 lies in the second quadrant, so we expect cos(7π/12) to be negative.
Recall that

which tells us

Now,

and so

I believe its already in vertex form