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ANEK [815]
3 years ago
10

Does (-1, 5) make the inequality y < 3x + 8 true?

Mathematics
2 answers:
Kobotan [32]3 years ago
7 0

Answer:

<u>(–1, 5) does NOT make </u><u><em>y</em></u><u> < 3</u><u><em>x</em></u><u> + 8 true.</u>

Step-by-step explanation:

First, let's substitute the values into the inequality. It's the one way to see if the point (–1, 5) is in the range of <em>y</em> < 3<em>x</em> + 8

5 ≟ 3(–1) + 8

5 ≟ 8 – 3

5 = 5 ✘

This means (–1, 5) does NOT make the inequality <em>y</em> < 3<em>x</em> + 8 true.

ioda3 years ago
3 0

Answer:

No

Step-by-step explanation:

as X=-1. and y=5

according to this y<3x+8

which means 5< 3*-1 +8

5<-3+8

5<5

which is not true.. as 5=5

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ki77a [65]
Total number of volunteer students for a committee = 7
Number of committee = 5

Number of ways of selecting the committee from the 7 volunteers = 7C5 = 7!/(5!*2!) = 21 ways.

There are 21 ways in which the 5-committee member can be selected from the 7 volunteers.
5 0
3 years ago
Help please! I asked this question three times and my session is about to start I really need to submit it.
hodyreva [135]

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Step-by-step explanation:

5 0
2 years ago
GreenBeam Ltd. claims that its compact fluorescent bulbs average no more than 3.50 mg of mercury. A sample of 25 bulbs shows a m
Harrizon [31]

Answer:

(a) Null Hypothesis, H_0 : \mu \leq 3.50 mg  

     Alternate Hypothesis, H_A : \mu > 3.50 mg

(b) The value of z test statistics is 2.50.

(c) We conclude that the average mg of mercury in compact fluorescent bulbs is more than 3.50 mg.

(d) The p-value is 0.0062.

Step-by-step explanation:

We are given that Green Beam Ltd. claims that its compact fluorescent bulbs average no more than 3.50 mg of mercury. A sample of 25 bulbs shows a mean of 3.59 mg of mercury. Assuming a known standard deviation of 0.18 mg.

<u><em /></u>

<u><em>Let </em></u>\mu<u><em> = average mg of mercury in compact fluorescent bulbs.</em></u>

So, Null Hypothesis, H_0 : \mu \leq 3.50 mg     {means that the average mg of mercury in compact fluorescent bulbs is no more than 3.50 mg}

Alternate Hypothesis, H_A : \mu > 3.50 mg     {means that the average mg of mercury in compact fluorescent bulbs is more than 3.50 mg}

The test statistics that would be used here <u>One-sample z test</u> <u>statistics</u> as we know about the population standard deviation;

                          T.S. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean mg of mercury = 3.59

            \sigma = population standard deviation = 0.18 mg

            n = sample of bulbs = 25

So, <em><u>test statistics</u></em>  =  \frac{3.59-3.50}{\frac{0.18}{\sqrt{25} } }

                               =  2.50

The value of z test statistics is 2.50.

<u>Now, P-value of the test statistics is given by;</u>

         P-value = P(Z > 2.50) = 1 - P(Z \leq 2.50)

                                             = 1 - 0.9938 = 0.0062

<em />

<em>Now, at 0.01 significance level the z table gives critical value of 2.3263 for right-tailed test. Since our test statistics is more than the critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which </em><em><u>we reject our null hypothesis</u></em><em>.</em>

Therefore, we conclude that the average mg of mercury in compact fluorescent bulbs is more than 3.50 mg.

6 0
3 years ago
Help me on this question
NeX [460]

Answer:

x = 18

Step-by-step explanation:

Vertically Opposite Angles are equal..

so,

x + 54 = 4x \\ 54 = 4x - x \\ 54 = 3x \\  \frac{54}{3} =    \frac{3x}{3}  \\ 18  = x

4 0
3 years ago
Read 2 more answers
A local coffee shop serves 2 9 as many customers as a shop run by a national coffee chain. The shop run by the chain serves 502
dexar [7]

I believe that it is 531 customers

6 0
3 years ago
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