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lisabon 2012 [21]
3 years ago
13

A rectangular house has a perimeter of 240 feet. The length of the house is 80 feet. What is the width of the house in feet?

Mathematics
1 answer:
fgiga [73]3 years ago
7 0

The perimeter of a rectangle is 2 times the length and 2 times the width. Since you got the perimeter (240), you can multiply 2 by the length (160) and subtract the perimeter (240) by it, giving you 80. This is 2 times the width. Divide that by 2 (divide 80 by 2) and you will get 40. The width is 40 feet.

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the length of a rectagle is 5 in longer than its width. if the perimeter of the rectangle is 56 in, find its length and width
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Answer:

Step-by-step explanation:

Let the width of the rectangle = x

As length is 5 inches longer than width, we have to add 5 to width

Length = x + 5

Perimeter of ractangle = 56 in

2* (length + width) = 56

2*( x + 5 + x) = 56

2* (2x + 5)    = 56

Use distributive property: a*(b +c) =(a*b) + (a * c)

2*2x + 2*5   = 56

4x  + 10 = 56

Subtract 10 from both sides

4x = 56- 10

4x = 46

Divide both sides by 4

x = 46/4

x = 11.5

Width = 11.5 in

length = 11.5 + 5

            = 16.5 in

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