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MAXImum [283]
2 years ago
5

laurens suv was detected exceeding the posted speed limit of 60 kilometers per hour , how many kilometers would she have been tr

aveling over the limit is she had covered a distance of 10 kilometers in 5 minutes?
Mathematics
1 answer:
Vlada [557]2 years ago
6 0

Answer:

60 kilometers per hour (kmph) over the limit

Step-by-step explanation:

The speed limit is 60 kmph

Let's find his original rate:

We know D = RT

Where

D is the distance, in km

R is the rate, in kmph

T is the time in hours

He went 10 km in 5 minutes, so we need the time in hours, first. That would be:

5/60 = 1/12 hour

So, putting into formula, we find rate:

D = RT

10 = R(1/12)

R = 10/(1/12)

R = 10 * 12

R = 120 kmph

He was going over by:

120 - 60 = 60 kmph

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3 years ago
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Answer:

1. Rewriting the expression 5.a.b.b.5.c.a.b.5.b using exponents we get: \mathbf{5^3a^2b^4c}

5.  x^-6 = \frac{1}{x^6}

6. 5^{-3}.3^{-1}=\frac{1}{5^3.3^1}

7. a^{-3}b^0c^4=\frac{c^4}{a^3}

Step-by-step explanation:

Question 1:

We need to rewrite the expression using exponents

5.a.b.b.5.c.a.b.5.b

We will first combine the like terms

5.5.5.a.a.b.b.b.b.c

Now, if we have 5.5.5 we can write it in exponent as: =5^{1+1+1}=5^3

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So, our result will be:

5^3a^2b^4c

Rewriting the expression 5.a.b.b.5.c.a.b.5.b using exponents we get: \mathbf{5^3a^2b^4c}

Question:

Rewrite using positive exponent:

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Applying thee above rule for getting the answers:

5) x^{-6} = \frac{1}{x^6}

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7) a^{-3}b^0c^4=\frac{b^0c^4}{a^3}

We know that b^0=1 so, we get

a^{-3}b^0c^4=\frac{b^0c^4}{a^3}=\frac{c^4}{a^3}

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3 years ago
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Answer:

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