Ten times as much as 3000

Mathematics

2 answers:

aev [14]3 years ago

8 0

That would be 30,000. Because since it is 10 times and 10 has one zero you would add one zero to 3,000 to get 30,000.

chubhunter [2.5K]3 years ago

3 0

Multiply 3000 by 10

10*3000=30000

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Use an equation to find the value of k

Delvig [45]

$\boxed{k=4}$

<h2>Explanation:</h2>

We know that the slope of a line is given by:

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \\ \\ Where: \\ \\ (x_{1},y_{1}) \ and \ (x_{2},y_{2}) \ are \ points \ that \ lie \ on \ the \ line \\ \\ \\ Here: \\ \\ (x_{1},y_{1})=(-2,k) \\ \\ (x_{2},y_{2})=(2,0) \\ \\ m=-1 \\ \\ \\ -1=\frac{0-k}{2-(-2)} \\ \\ -1=\frac{-k}{4} \\ \\ -k=4(-1) \\ \\ \boxed{k=4}$

<h2>Learn more:</h2>

Proportional relationships lines, rates of change, and slope:

brainly.com/question/674693

#LearnWithBrainly

4 0

3 years ago

Without plotting points, let M=(-2,-1), N=(3,1), M'= (0,2), and N'=(5, 4). Without using the distanceformula, show that segments

kramer

Given:

M=(x1, y1)=(-2,-1),

N=(x2, y2)=(3,1),

M'=(x3, y3)= (0,2),

N'=(x4, y4)=(5, 4).

We can prove MN and M'N' have the same length by proving that the points form the vertices of a parallelogram.

For a parallelogram, opposite sides are equal

If we prove that the quadrilateral MNN'M' forms a parallellogram, then MN and M'N' will be the oppposite sides. So, we can prove that MN=M'N'.

To prove MNN'M' is a parallelogram, we have to first prove that two pairs of opposite sides are parallel,

Slope of MN= Slope of M'N'.

Slope of MM'=NN'.

$\begin{gathered} \text{Slope of MN=}\frac{y2-y1}{x2-x1} \\ =\frac{1-(-1)}{3-(-2)} \\ =\frac{2}{5} \\ \text{Slope of M'N'=}\frac{y4-y3}{x4-x3} \\ =\frac{4-2}{5-0} \\ =\frac{2}{5} \end{gathered}$

Hence, slope of MN=Slope of M'N' and therefore, MN parallel to M'N'

$\begin{gathered} \text{Slope of MM'=}\frac{y3-y1}{x3-x1} \\ =\frac{4-(-1)}{5-(-2)} \\ =\frac{3}{2} \\ \text{Slope of NN'=}\frac{y4-y2}{x4-x2} \\ =\frac{4-1}{5-3} \\ =\frac{3}{2} \end{gathered}$

Hence, slope of MM'=Slope of NN' nd therefore, MM' parallel to NN'.

Since both pairs of opposite sides of MNN'M' are parallel, MM'N'N is a parallelogram.

Since the opposite sides are of equal length in a parallelogram, it is proved that segments MN and M'N' have the same length.